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Two charges eachof q=+2 micro coloumb are placed at the vertices Q and R of the triangle .the sum of sides PQ and PR is 12cm and their product is 32 cm_2 .the potential at point P is?Solution) In ΔPQR, Let PQ=8cm PR=4cmAt P, V=9*109 {(2/4) + (2/8)}*10-6*102 = 9*109*(3/4)*10-4 = 6.75*105
hi, can you help me with sage homwork about physics
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