efficient algorithms.., Data Structure & Algorithms

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implementation of fast fourier transforms for non power of 2

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Stack, Explain the array and linked list implementation of stack

Explain the array and linked list implementation of stack

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Memory Allocation Strategies If it is not desirable to move blocks of due storage from one area of memory to another, it must be possible to relocate memory blocks that have be

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Explain an efficient way of storing a sparse matrix in memory.   A matrix in which number of zero entries are much higher than the number of non zero entries is called sparse mat

Depth-First Traversal, With the help of a program and a numerical example e...

With the help of a program and a numerical example explain the Depth First Traversal of a tree.

Write down the procedure to reverse a singly linked list. , Ans: A pr...

Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;

Representation of records, Records are mapped onto a computer store by simp...

Records are mapped onto a computer store by simply juxtaposing their elements. The address of a component (field) r relative to the origin address of the record r is named the fiel

Algorithm to merge the lists together, Q. Let X = (X1, X2, X3,....Xn) and Y...

Q. Let X = (X1, X2, X3,....Xn) and Y= (Y1, Y2, Y3,....Xm) be the two linked lists respectively. Write down an algorithm to merge the lists together to get the linked list Z such th

Define chaining process of hashing, Chaining In this method, instead of...

Chaining In this method, instead of hashing function value as location we use it as an index into an array of pointers. Every pointer access a chain that holds the element havi

Time complexity, Run time complexity of an algorithm is depend on

Run time complexity of an algorithm is depend on

Linear array - numerical, Q. A linear array A is given with lower bound as ...

Q. A linear array A is given with lower bound as 1. If address of A[25] is 375 and A[30] is 390, then find address of A[16].

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