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Each of the comparison in the binary search decrease the number of possible candidates where the key value can be searched by a factor of 2 as the array is divided into two halves in each iteration. Therefore, the maximum number of key comparisons is about log n. Thus, the order of binary search is O (log n).
Any Binary search tree has to contain following properties to be called as a red- black tree. 1. Each node of a tree must be either red or black. 2. The root node is always b
Q. Explain the technique to calculate the address of an element in an array. A 25 × 4 matrix array DATA is stored in memory in 'row-major order'. If base address is 200 and
A linear list of elements in which deletion can be done from one end (front) and insertion can take place only at the other end (rear) is called as a Queue.
Q. Consider the specification written below of a graph G V(G ) = {1,2,3,4} E(G ) = {(1,2), (1,3), (3,3), (3,4), (4,1)} (i) Draw the undirected graph. (
Q. Write down a non recursive algorithm to traverse a binary tree in order. Ans: N on - recursive algorithm to traverse a binary tree in inorder is as
2. Write a note on i) devising ii) validating and iii) testing of algorithms.
Binary Search Tree usage: Write a program to compare the time taken for a search in a skewed tree, a balanced tree, and a random tree. Specically, your program should do the
Q. What do you understand by the tree traversal? Write down the procedure for traversing a binary tree in preorder and execute it on the following tree. Ans: Th
Write an algorithm to test whether a Binary Tree is a Binary Search Tree. The algorithm to test whether a Binary tree is as Binary Search tree is as follows: bstree(*tree) {
Merging 4 sorted files having 50, 10, 25 and 15 records will take time
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