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Each of the comparison in the binary search decrease the number of possible candidates where the key value can be searched by a factor of 2 as the array is divided into two halves in each iteration. Therefore, the maximum number of key comparisons is about log n. Thus, the order of binary search is O (log n).
include int choice, stack[10], top, element; void menu(); void push(); void pop(); void showelements(); void main() { choice=element=1; top=0; menu()
Define tractable and intractable problems Problems that can be solved in polynomial time are known as tractable problems, problems that cannot be solved in polynomial time are
The size of stack was declared as ten. Thus, stack cannot hold more than ten elements. The major operations which can be performed onto a stack are push and pop. However, in a prog
What will be depth do , of complete binary tree of n nodes, where nodes are labelled from 1 to n with root as node and last leaf node as node n
Open addressing The easiest way to resolve a collision is to start with the hash address and do a sequential search by the table for an empty location.
What are the structures used in file-system implementation? Several on-disk and in-memory structures are used to execute a file system a. On-disk structure include P
Readjusting for tree modification calls for rotations in the binary search tree. Single rotations are possible in the left or right direction for moving a node to the root position
This method is the reverse of FIFO and assumes that each issue of stock is made from latest items received in the enterprises .Thus if the last lot to be received is not sufficient
Q. Define a sparse matrix. Explain different types of sparse matrices? Show how a triangular array is stored in memory. Evaluate the method to calculate address of any element ajk
Question 1 What is a data structure? Discuss briefly on types of data structures Question 2 Explain the insertion and deletion operation of linked list in detail Question
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