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MyLocation SDWORD 14TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebxShow exactly what lives in eax after execution of the above code (Hint: Answer in hex pairs).TestArray WORD 3 DUP (0), 5,6,7 Test1 DWORD LENGTHOF TestArray Test2 DWORD TYPE TestArray Test3 DWORD SIZEOF TestArrayShow exactly what lives in Test1, Test2 and Test3 after execution of the above code. (Hint: Answer each as hex pairs).TheArray WORD A1h, B2h, C3h, D4h mov eax, 0 mov ax, [TheArray+6]Show exactly what lives in ax after execution of the above code. (Hint: Answer in hex pairs).
code to add two matrices
Assembly Language Example Programs We studied the entire instruction set of 8086/88, pseudo-ops and assembler directives. We have explained the process of entering an assembly
RCR: Rotate Right through Carry:- This instruction rotates the contents bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati
which uses BIOS interrupt INT 21 to read current system time and displays it on the top-left corner of screen.
#questioexamplesn..
You are to write an assembly language program called subfaq.s that computes the generalized subfactorial function of nonnegative integer inputs i0 and n. The generalized subfactori
a- Trace the following program fragment and find out the content of ax after the the execution of the program. X db 5,7 -3,-9,4,-7,9 Mov
write and run a programme using 8086 assembly language that interchange the lower four bits of AL registered with upper four bits.
init_lcd ;(this initialises a 2 row lcd) bcf TRISA,0 ;PORTA bit 0 as an output (lcd RS pin) bcf TRISA,1 ;PORTA bit 1
Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention
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