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MyLocation SDWORD 14TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebxShow exactly what lives in eax after execution of the above code (Hint: Answer in hex pairs).TestArray WORD 3 DUP (0), 5,6,7 Test1 DWORD LENGTHOF TestArray Test2 DWORD TYPE TestArray Test3 DWORD SIZEOF TestArrayShow exactly what lives in Test1, Test2 and Test3 after execution of the above code. (Hint: Answer each as hex pairs).TheArray WORD A1h, B2h, C3h, D4h mov eax, 0 mov ax, [TheArray+6]Show exactly what lives in ax after execution of the above code. (Hint: Answer in hex pairs).
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
CISC Characteristics : The design of an instruction set for a computer might take into consideration not only machine language constraints, but also the requirements i
write a programme the addition two 3*3 matrix and stored in from list
Why is the capability to relocate processes desirable?
DMA controller : Steps include in transferring a block of data from I/O devices (for example a disk) to memory: 1. CPU sends a signal to initiate disk transfe
ROR : Rotate Right without Carry: This instruction rotates the contents of destination operand to the bit-wise right either by one or by the count specified in register CL, exclud
64-bit integer calculator, which processes using 16-bits at a time (reg/mem16 operands)
External System Bus Architecture : This is a 16 bit processor with 40 pins. It has twenty address pins and out of which sixteen are utilized as data pins. This concept of by us
Opcode : The opcode generally appear in the first byte.but in a few instructions, a register objective is in the first byte and few other instructions may have their 3-bits of
how o create the flow chart for scan ROW4, Column 1 and 3.tq
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