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MyLocation SDWORD 14TheTest SDWORD 8 mov eax,MyLocation mov ebx,TheTest neg eax,ebx sub eax,ebxShow exactly what lives in eax after execution of the above code (Hint: Answer in hex pairs).TestArray WORD 3 DUP (0), 5,6,7 Test1 DWORD LENGTHOF TestArray Test2 DWORD TYPE TestArray Test3 DWORD SIZEOF TestArrayShow exactly what lives in Test1, Test2 and Test3 after execution of the above code. (Hint: Answer each as hex pairs).TheArray WORD A1h, B2h, C3h, D4h mov eax, 0 mov ax, [TheArray+6]Show exactly what lives in ax after execution of the above code. (Hint: Answer in hex pairs).
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
NEG: Negate:- The negate instruction forms the 2's complement of the particular destination in the instruction. For obtaining 2's complement, it subtracts the contents of destinat
what is sahf nstrucions
what is implied addressing
Problem (a) Prepare the assembly code sequence for each of the four styles (accumulator, memory-memory, stack, load/store) of machine for the code fragment: A = B + C;
Write an assembly language program that will display (print) a list of the Decades 2010, 2020, 2030... 2100 to the screen using a while loop.
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H..
Displacement addressing technique
Signal descriptions of 8086 : described below are common for the maximum andminimum mode bothdata lines AD15 -AD0: These are the time multiplexed andmemory I/O address. Addre
I can get it to copy the string but can''t get it to reverse it.
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