Dynamically induced emf and statically induced emf, Mechanical Engineering

Assignment Help:

Q. What is meant by dynamically induced emf and statically induced emf? On what factors do these depend? Derive eq. for these two emfs.

 

Sol. Dynamically induced emf:

Consider a conductor of length l m placed in a uniform magnetic field of density B wb/m2.

 

Let this conductor be moved with velocity Vm/sec in the direction of field. In this case no flux is cut by conductor, therefore. No emf is induced.

Now if this conductor is moved with the velocity v m/s in a direction perpendicular to its own length and perpendicular to the direction of the magnetic field. Flux is cut by conductor therefore, an emf is induced in the conductor.

Area swept per sec. by the conductor = l × v m2/sec

 

Flux cut per sec. = flux density × area swept per sec. = Blv

 

Rate of change of flux, d φ/dt

 

Flux cut per sec. = Blv wb/sec

 

Induced emf, e = d φ/dt = Blv volts

 

The magnitude of emf induced is proportional to the components of the velocity in a direction perpendicular  to the direction of the magnetic field and induced emf is given by

 

        E = Blv sinθ volts

 

 Statically induced emf

 Self induced emf :

 Consider a solenoid of N turns, length l m, area of x- section a square meters and of relatively permeability µr. When the solenoid carries a current of I amperes, a magnetic field of flux µi/l/ µo µra weber is set up around the solenoid and links with it.

 

If the current flowing through the solenoid is changed., the flux produced by it will change and therefore, an emf will be induced.

 

               Self induced emf e = -µ dΦ/dt

 

                           = - µ d/dt [µ/l/ µo µra di/dt = - µ2 µr µoa.di/dt


Related Discussions:- Dynamically induced emf and statically induced emf

Evaluate the deflection at the free end of the cantilever, Evaluate the def...

Evaluate the deflection at the free end of the cantilever: Discover the slope and deflection at the free end of the cantilever illustrated in Figure . Take EI = 200 × 10 6 N-

Fuel and steam generator, Boiler efficiency and heat losses, heat Balence s...

Boiler efficiency and heat losses, heat Balence sheet, boiler draught, high pressure boiler

Describe crank-pin effort, Describe the following terms:- a) Gyroscope ...

Describe the following terms:- a) Gyroscope b) Crank-pin effort c) Piston Effort d) Crank effort e) Thrust on crank shaft bearings.  f) Brake and Dynamometer g

Determine the centroid of the truss gusset plate, Determine the centroid of...

Determine the centroid of the truss Gusset Plate shown in figure below.

System of parallel forces - mechanics, System of parallel forces: A r...

System of parallel forces: A rigid body is subjected to system of parallel forces as shown in the figure. Reduce this system to, ( i ) A single force system ( i

Hydraulic ram, definition and picture of hyreaulic ram

definition and picture of hyreaulic ram

Pumps, three indications of centrifugal pump cavitating

three indications of centrifugal pump cavitating

Spray up method, Spray up method In a slight variation, to suit the ne...

Spray up method In a slight variation, to suit the necessity of bigger size parts the fibre resin and rovings are fed concurrently. The fibre rovings are fed via a chopper whe

LPP, (Hint Minimization problem -min X1 + X2, s.t. 2X1 + X2 = 12, X1 + 6X2 ...

(Hint Minimization problem -min X1 + X2, s.t. 2X1 + X2 = 12, X1 + 6X2 = 24, 5X1 + 8X2 = 24; X1, X2 = 0).

Automated material handling, Automated Material Handling We have dealt...

Automated Material Handling We have dealt along with the automated guided vehicles and Robots utilized in the industry. Because of the industrial automation, various changes h

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd