Dynamically induced emf and statically induced emf, Mechanical Engineering

Assignment Help:

Q. What is meant by dynamically induced emf and statically induced emf? On what factors do these depend? Derive eq. for these two emfs.

 

Sol. Dynamically induced emf:

Consider a conductor of length l m placed in a uniform magnetic field of density B wb/m2.

 

Let this conductor be moved with velocity Vm/sec in the direction of field. In this case no flux is cut by conductor, therefore. No emf is induced.

Now if this conductor is moved with the velocity v m/s in a direction perpendicular to its own length and perpendicular to the direction of the magnetic field. Flux is cut by conductor therefore, an emf is induced in the conductor.

Area swept per sec. by the conductor = l × v m2/sec

 

Flux cut per sec. = flux density × area swept per sec. = Blv

 

Rate of change of flux, d φ/dt

 

Flux cut per sec. = Blv wb/sec

 

Induced emf, e = d φ/dt = Blv volts

 

The magnitude of emf induced is proportional to the components of the velocity in a direction perpendicular  to the direction of the magnetic field and induced emf is given by

 

        E = Blv sinθ volts

 

 Statically induced emf

 Self induced emf :

 Consider a solenoid of N turns, length l m, area of x- section a square meters and of relatively permeability µr. When the solenoid carries a current of I amperes, a magnetic field of flux µi/l/ µo µra weber is set up around the solenoid and links with it.

 

If the current flowing through the solenoid is changed., the flux produced by it will change and therefore, an emf will be induced.

 

               Self induced emf e = -µ dΦ/dt

 

                           = - µ d/dt [µ/l/ µo µra di/dt = - µ2 µr µoa.di/dt


Related Discussions:- Dynamically induced emf and statically induced emf

Dom, what is offset inertia force

what is offset inertia force

Lap-type flange-to-shell clearance, Q. Lap-Type Flange-To-Shell Clearance? ...

Q. Lap-Type Flange-To-Shell Clearance? Lap-Type Flange-To-Shell Clearance The difference between the flange ID and the shell OD shall not exceed: • 1/16 in (1.6 mm) for n

Blade tips with burrs, Industrial had been producing various types of medic...

Industrial had been producing various types of medical products. One of the manufacture lines is Blade Department. Recently we had received a complained from Headquarter regarding

Energy accelerated, Ask question EMC#Minimum 100 words accepted#

Ask question EMC#Minimum 100 words accepted#

Optimal feeder geometry, PART A A new process plant for ore processing ...

PART A A new process plant for ore processing is currently being planned. The design is only in the first stage. However, three requirements have already been clearly stated:

Truss arrangement assuming the members are beams, Q2.1  Using the stiffness...

Q2.1  Using the stiffness method calculate axial forces and the deflections of the joints of the truss shown in the FIG. The truss was built using 50 mm x 50 mm x 5 mm SHS with  E

Discover the suitable diameter of the shaft, Discover the suitable diameter...

Discover the suitable diameter of the shaft: A shaft is required to fail while the torque on the shaft is 20 kN-m. Discover the suitable diameter of the shaft of the modulus o

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd