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How memory is freed using Boundary tag method in the context of Dynamic memory management?
Boundary Tag Method to free Memory
To delete an arbitrary block from the free list (to join it with a newly freed block) without traversing whole list, the free list must be doubly linked. Therefore each free block must have 2 pointers, next and prev to the next and last free block on the free block. (This is needed when joining a newly freed block with a free block that immediately proceeds in memory).
Q. Give the algorithm for the selection sort. Describe the behaviours of selection sort when the input given is already sorted.
reverse the order of elements on a stack S using two additional stacks using one additional stack
Simulation is the process of making an abstract model of a real world situation in order to be aware of the effect of modifications and alterations and the effect of introducing nu
A Stack has an ordered list of elements & an array is also utilized to store ordered list of elements. Therefore, it would be very simple to manage a stack by using an array. Thoug
Aa) Come up with an ERD from the following scenario, clearly stating all entities, attributes, relationships before final sketch of the ERD: [50 m
Explain an efficient way of storing two symmetric matrices of the same order in memory. A n-square matrix array is said to be symmetric if a[j][k]=a[k][j] for all j and k. For
Q. What do you understand by the tree traversal? Write down the procedure for traversing a binary tree in preorder and execute it on the following tree. Ans: Th
Your first task will be to come up with an appropriate data structure for representing numbers of arbitrary potential length in base 215. You will have to deal with large negative
Define container in terms of object-oriented terms A Container is a broad category whose instances are all more specific things; there is never anything which is just a Contai
Inorder traversal: The left sub tree is visited, then the node and then right sub-tree. Algorithm for inorder traversal is following: traverse left sub-tree visit node
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