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Usually memory is allocated from a large pool of unused memory area called the heap. In C++, dynamic allocation/deallocation must be manually performed using commands like malloc, free, new and delete. Malloc allocates space of a given size and gives a pointer back to the programmer. The programmer then can do whatever he or she wants with it. The new command, on the other hand, allocates a speci?c object of a given size. The general way in which dynamic allocation is done is that the program asks the memory manager to allocate or free objects (or multiple pages); then, the memory manager asks the OS to allocate/free pages (or multiple pages). Notice, how- ever, that the allocator does not give the whole allocated page back to the program; it just gives what it asked for. The rest of the page (i.e. the parts not given to the program) is saved for future memory requests.
(Add synchronization to your solutions to HW 3 to eliminate all of the race conditions. You should not remove any of the sleep() commands that you used to produce the race conditi
What is the basic approach of page replacement? If no frame is free is available, find one that is not presently being used and free it. A frame can be freed by writing its con
The question of fairness, regarding page eviction, is a hard one. How do we decide what is fair? Many operating systems use global LRU, where pages from all processes are managed t
Before proceeding with its execution, every process must obtain all the resources it needs is called Hold and wait
List the four steps that are essential to run a program on a completely dedicated machine. a. Reserve machine time. b. Manually load program into memory. c. Load starting
Briefly discuss on Bankers algorithm? The resource-allocation graph algorithm is not applicable to a resource-allocation system with multiple examples for each resource type.
what is the meaning of co-operating process?
What is input output operation ?
Q. Explain a mechanism by which one segment could belong to the address space of two different processes. Answer: Because segment tables are a collection of base-limit register
Did Abhinav agree to the initial timeline requested by Rebecca
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