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Dynamic Initialization of objects:
It is initializing the objects by passing the valued to the constructor from the user input or
other means. Through cin operator a value can be stored in a variable and passed through a constructor this form of initializing an object is known dynamic initialization.
Dynamic Constructor:
The memory allocation for a constructor can be managed using new operator called new,
similarly the memory can be free with another operator called deleter.
class dynmem
{ char *name;
int length;
public:
dynmem(void)
{length =0;
name = new char[length+1];
}
dynmem(char *s)
{length = strlen(s);
name = new char[length+1];//for null terminator
strcpy(name,s);
void display(void)
{cout< } void join(dynmem &a, dynmem &b); }; void dynmem::join(dynmem &a, dynmem &b) {length = a.length+b.length; delete name; name = new char[length+1]; strcpy(name,a.name); strcat(name,b.name); }; void main() { clrscr(); char *first="Electronic "; dynmem name1(first); dynmem name2("and Communication "); dynmem name3("Engineering"); dynmem s1,s2; s1.join(name1,name2); s2.join(s1,name3); name1.display(); name2.display(); name3.display(); s1.display(); s2.display(); }
void join(dynmem &a, dynmem &b);
};
void dynmem::join(dynmem &a, dynmem &b)
{length = a.length+b.length;
delete name;
name = new char[length+1]; strcpy(name,a.name); strcat(name,b.name);
void main()
{
clrscr();
char *first="Electronic ";
dynmem name1(first);
dynmem name2("and Communication ");
dynmem name3("Engineering"); dynmem s1,s2; s1.join(name1,name2); s2.join(s1,name3); name1.display();
name2.display(); name3.display(); s1.display(); s2.display();
My project is compiling but the equation entered is not working
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