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DQ: Define Quad word:-
This directive is taken in use to direct the assembler to reserve 4 words (8 bytes) of memory for the specified variable and can initialise it having the specified values.
DT: Define Ten Bytes:-
The DT directive directs the assembler to define the specified variable requiring 10- bytes for its storage and initialise the 10-bytes with the specified values. The directive may be used in case of variables facing heavy numerical calculations, normally processed by numerical processors.
from pin description it seems that 8086 has 16 address/data lines i.e.AD0_AD15.The physical address is however is larger than 2^16.How this condition can be handled
Architecture Of 8088 The register set of 8088 is accurately the same as in to 8086. The architecture of 8088 is also same to 8086 except for 2 changes; a) 8088 has 4-byte instr
REP : Repeat Instruction Prefix :- This instruction is utilized as a prefix to other instructions. The instruction in which the REP prefix is provided, is executed repetitively
External Hardware-Interrupts External hardware-interrupts are generated by controllers of external devices or coprocessors and are connected to the processor pin for Non Mask a
Programming with an assembler The procedure of hand-coding 8086 programs is somewhat tiresome; hence generally a programmer may find it hard to get a correct listing of the mac
Description: LC3 allows input from keyboard and output to display on the screen. This lab will exercise the input/output capability using LC-3 Assembly language. Procedure
Print Media Advertising (PMA) has been providing a contract to market Buzz Cola via newspaper ads in a main southern newspaper. Full-page ads in the weekday editions (Monday throug
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Interrupt Table Each interrupt level has a booked memory location, called an interrupt vector. All these vectors (or pointers) are stored in the interrupt table. Table lies at
Problem (a) Prepare the assembly code sequence for each of the four styles (accumulator, memory-memory, stack, load/store) of machine for the code fragment: A = B + C;
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