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According to this, key value is divided by any fitting number, generally a prime number, and the division of remainder is utilized as the address for the record.
The choice of suitable divisor may not be so simple. If it is known that the file is to have n records, then we has to, assuming that only one record can be stored at a given address, have divisor n.
Also we might have a very large key space as compared to the address space. Key space refers to every possible key value. The address space possibly may not match in fact for the key values in the file. So, calculated address may not be unique. It is called Collision, that means
R(K1) = R(K2), where K1 = K2.
Two unequal keys have been calculated to have the simialr address. The keys are called as synonyms.
There are several approaches to handle the problem of collisions. One of these is to hash to buckets. A bucket is a space that can suggest multiple records.
write short note on algorithms
Write an algorithm, using a flowchart, which inputs the heights of all 500 students and outputs the height of the tallest person and the shortest p erson in the school.
Define Complete Binary Tree Complete Binary Tree:- A whole binary tree of depth d is that strictly binary tree all of whose leaves are at level D.
State the range of operation of ADT Operations of the Range of T ADT includes following, where a, b ∈ T and r and s are values of Range of T: a...b-returns a range value (an
Write an algorithm for binary search. Algorithm for Binary Search 1. if (low> high) 2. return (-1) 3. Mid = (low + high)/2 4. if ( X = = a[mid]) 5. return (mid); 6.
AVL trees are applied into the given situations: There are few insertion & deletion operations Short search time is required Input data is sorted or nearly sorted
Since memory is becoming more & cheaper, the prominence of runtime complexity is enhancing. However, it is very much significant to analyses the amount of memory utilized by a prog
null(nil) = true // nil refer for empty tree null(fork(e, T, T'))= false // e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true leaf(
Do you have a library solution for this problem?
Breadth-first search starts at a given vertex h, which is at level 0. In the first stage, we go to all the vertices that are at the distance of one edge away. When we go there, we
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