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Dividing Whole Numbers:
Example:
Divide 347 by 5.
Solution:
Beginning from the left of the dividend, the divisor is divided into the 1st digit or set of digits it divides into. In that case, 5 is divided into 34; the result is 6 that is placed above the 4.
This result (6) is then multiplied through the divisor, and the product is subtracted from the set of digits in the dividend first chosen. 6 x 5 equals 30; 30 subtracted from 34 equals 4.
The further digit to the right in the dividend is then brought down, and the divisor is divided within this number. In this case, the 7 is brought down, and 5 is divided into 47; the output is 9, that is placed above the 7.
Again, this result is multiplied by the divisor, & the product is subtracted to the last number used for division. 9 x 5 equals 45 and 45 subtracted from 47 equals 2. This procedure is repeated until all of the digits in the dividend have been brought down. In that case, there are no more digits in the dividend. The output of the last subtraction is the remainder. A number placed above the dividend is the quotient. In this case, 347 ÷ 5 yields a quotient of 69 along with a remainder of 2.
#question Show that the enveloping cylinder of the conicoid ax 2 + by 2 + cz 2 = 1 with generators perpendicular to the z-axis meets the plane z = 0 in parabolas
( a+2b)x + (2a - b)y = 2, (a - 2b)x + (2a +b)y = 3 (Ans: 5b - 2a/10ab , a + 10b/10ab ) Ans: 2ax + 4ay = y , we get 4bx - 2by = -1 2ax+ 4ay = 5 4bx- 2by = - 1
i really ned help wiv quartiles plz help
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