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DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in the register AX for 16-bit operation and divisor might be specified by using any one of the addressing modes accept immediate. The result will be in the register AL (quotient) while register AH will contain the remainder. If the result is too big to fit in register AL, type 0 (divide by zero) interrupt is produced. In case of a double word dividend (32-bit), the higher word should be in register DX and lower word should be in the register AX. The divisor might be specified as already explained. The remainder and quotient , in this type of case, will be in AX and DX respectively. This instruction does not make any affect on any flag.
IDIV: Signed Division:- This instruction performs the similar operation as the DIV instruction, but with signed operands. The results are stored similarly as in case of DIV instruction in both cases of word and double word divisions. The results will be also signed numbers. The operands are also specified in the similar way as DIV instruction. Divide by 0 interrupt is produced, if the result is too big to fit in register AX (16-bit dividend operation) or register AX and register DX (32-bit dividend operation). All the flags are undefined after IDIV instruction.
LENGTH : Byte Length of a Label: This directive is not available in MASM. This is used to mention to the length of a data array or a string. MOV CX. LENGTH ARRAY This sta
SUB: Subtract :- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory locati
Description Write a MIPS program that reads a string from user input, reverse each word (defined as a sequence of English alphabetic letters or numeric digits without any punctu
Write a program that performs the addition, subtraction, multiplications, division of the given operands. Perform BCD operation for addition and subtraction.
Entering a Program In this section, we will explain the procedure for entering a small program on IBM PC with DOS operating system. Assume a program of addition of 2 bytes, as
Hello, I just want to know how much would it cost for you to develop , debug and test a program in matlab to solve a system of equations with gauss elimination with partial pivotin
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Assembly Code for Reading Flow & Generating Serial Output The timer is timer 1 is set for the baud rate 9600, as the crystal used is of 11.0592 Hz. Then the timer 1 is starte
8279 Keyword /Display Controller : Figure shows the structure of 8279 and its interface to the bus. Addressing is according to the table given below. CS RD
Internal Hardware-Interrupts Internal hardware-interrupts are the outcome of sure situations that occur during the execution of a program, for example. Divide by 0. The interru
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