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DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in the register AX for 16-bit operation and divisor might be specified by using any one of the addressing modes accept immediate. The result will be in the register AL (quotient) while register AH will contain the remainder. If the result is too big to fit in register AL, type 0 (divide by zero) interrupt is produced. In case of a double word dividend (32-bit), the higher word should be in register DX and lower word should be in the register AX. The divisor might be specified as already explained. The remainder and quotient , in this type of case, will be in AX and DX respectively. This instruction does not make any affect on any flag.
IDIV: Signed Division:- This instruction performs the similar operation as the DIV instruction, but with signed operands. The results are stored similarly as in case of DIV instruction in both cases of word and double word divisions. The results will be also signed numbers. The operands are also specified in the similar way as DIV instruction. Divide by 0 interrupt is produced, if the result is too big to fit in register AX (16-bit dividend operation) or register AX and register DX (32-bit dividend operation). All the flags are undefined after IDIV instruction.
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H
You have to write a subroutine (assembly language code using NASM) for the following equation.
Programming with an assembler The procedure of hand-coding 8086 programs is somewhat tiresome; hence generally a programmer may find it hard to get a correct listing of the mac
Interrupt System Based on Multiple 8259As A multiple 8259A interrupt system is diagrammed in given figure in this figure data bus drivers are not indicated, but they could be i
Ask question #MinimuWHAT ARE CONSTANTS AND WHAT DO THEY DO?m 100 words accepted#
I need to estimate the value of a definite integral using Riemann Sums and For our estimation let f(x) = x2 ,a=0, b=10 and n=5. Where a is the lower bound, b is the upper bound and
CMP: Compare: - This instruction compares the source operand, which can be a register or memory location an immediate data with a destination operand that might be a register or a
add the contents of the defined memory locations 120, 133, 122 using mov instruction in dosbox
1. The microwave has a clock (hh:mm:ss am/pm) and the user should be able to change the clock at any time. 2. For cooking the user should first enter the time. The user can ente
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