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DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in the register AX for 16-bit operation and divisor might be specified by using any one of the addressing modes accept immediate. The result will be in the register AL (quotient) while register AH will contain the remainder. If the result is too big to fit in register AL, type 0 (divide by zero) interrupt is produced. In case of a double word dividend (32-bit), the higher word should be in register DX and lower word should be in the register AX. The divisor might be specified as already explained. The remainder and quotient , in this type of case, will be in AX and DX respectively. This instruction does not make any affect on any flag.
IDIV: Signed Division:- This instruction performs the similar operation as the DIV instruction, but with signed operands. The results are stored similarly as in case of DIV instruction in both cases of word and double word divisions. The results will be also signed numbers. The operands are also specified in the similar way as DIV instruction. Divide by 0 interrupt is produced, if the result is too big to fit in register AX (16-bit dividend operation) or register AX and register DX (32-bit dividend operation). All the flags are undefined after IDIV instruction.
Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention
how to store a bulk data in a external eeprom
Motorola 68000 Series : 68000microprocessor is a 16 bit processor that has addressing space of 65536 locations, each of which holds a 64-bits word; In order to address those lo
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Your assignment for this project is to write an assembly language program that checks if the user's input is a valid ISBN number. A sample run of your program might look like:
PLEASE MAY YOU ASSIST ME WITH SAMPLE CODES FOR PROGRAMING A FIRE ALARM MINI PROJECT
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
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(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil
Convert 751 to hex and show what it would look like stored at TheNumber WORD ? (hint: answer in hex pairs)
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