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DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in the register AX for 16-bit operation and divisor might be specified by using any one of the addressing modes accept immediate. The result will be in the register AL (quotient) while register AH will contain the remainder. If the result is too big to fit in register AL, type 0 (divide by zero) interrupt is produced. In case of a double word dividend (32-bit), the higher word should be in register DX and lower word should be in the register AX. The divisor might be specified as already explained. The remainder and quotient , in this type of case, will be in AX and DX respectively. This instruction does not make any affect on any flag.
IDIV: Signed Division:- This instruction performs the similar operation as the DIV instruction, but with signed operands. The results are stored similarly as in case of DIV instruction in both cases of word and double word divisions. The results will be also signed numbers. The operands are also specified in the similar way as DIV instruction. Divide by 0 interrupt is produced, if the result is too big to fit in register AX (16-bit dividend operation) or register AX and register DX (32-bit dividend operation). All the flags are undefined after IDIV instruction.
SUB: Subtract :- The subtract instruction subtracts the source operand from destination operand and result is left in the destination operand. Source operand might be memory locati
Machine Level Programs In this section, a few machine levels programming instance, rather then, instruction sequences are presented for comparing the 8086 programming with that
Write an assembly language program that will: accept keyboard input of a positive integer value N; compute the sum S= 1+ 2 + 3 + ... + N; print (output) the computed su
move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H
8279 Keyword /Display Controller : Figure shows the structure of 8279 and its interface to the bus. Addressing is according to the table given below. CS RD
Ask(2) Write a program to mask bits D3D2D1D0 and to set bits D5D4 and to invert bits D7D6 of the AX register question #Minimum 100 words accepted#
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Multiply two numbers by using shift and rotate instruction
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
1. Write an assembly program that adds the elements in the odd indices of the following array. Use LOOP. What is the final value in the register? array1 DWORD 10, 20, 30, 40, 50, 6
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