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DIV: Unsigned Division:- This instruction performs unsigned division operation. It divides an unsigned word or double word by a 16-bit or 8-bit operand. The dividend might be in the register AX for 16-bit operation and divisor might be specified by using any one of the addressing modes accept immediate. The result will be in the register AL (quotient) while register AH will contain the remainder. If the result is too big to fit in register AL, type 0 (divide by zero) interrupt is produced. In case of a double word dividend (32-bit), the higher word should be in register DX and lower word should be in the register AX. The divisor might be specified as already explained. The remainder and quotient , in this type of case, will be in AX and DX respectively. This instruction does not make any affect on any flag.
IDIV: Signed Division:- This instruction performs the similar operation as the DIV instruction, but with signed operands. The results are stored similarly as in case of DIV instruction in both cases of word and double word divisions. The results will be also signed numbers. The operands are also specified in the similar way as DIV instruction. Divide by 0 interrupt is produced, if the result is too big to fit in register AX (16-bit dividend operation) or register AX and register DX (32-bit dividend operation). All the flags are undefined after IDIV instruction.
I/O interface I/O devices such as displays and keyboards establish communication of computer with outside world. Devices may be interfaced in 2 ways Memory mapped I/O and I/
SHL/SAL : Shift logical/Arithmetic Left: These instructions shift the operand byte or word bit by bit to the left and insert 0 in the newly introduced least significant bits. In c
8086 Minimum mode System and Timing In a minimum mode 8086 system, the microprocessor 8086 is operated in minimum mode by strapping its MN/MX pin to logic 1.All the control si
Assembling a program Microsoft Assembler MASM is one of the simple to use and famous assemblers. All the references and discussions in this section are belonging to the MASM.
Can any one assist me with this program. I am not efficient with assembly language and I need assistance badly. I am not asking anyone to do my work I just need help step by step
Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
I am assigned to implement dijkstra algorithm in assembly language. I am not a novice in assembly. I need help implementing it.Kindly if anyone then please.
calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction
8088 Timing System Diagram The 8088 address/data bus is divided in 3 parts (a) the lower 8 address/data bits, (b) the middle 8 address bits, and (c) the upper 4 status/
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