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Display control
8279 provides a 16 byte display memory and refresh logic. Every address in the display memory corresponds to a display unit with address zero representing the leftmost display unit. Output is accomplished by 8279 again and again sending out characters over the lines OUT A3-A0 and OUT B3-B0 and unit chooses address is over SL3-SL0.
For the auto increment left entry, after every writes to the display the addresses incremented by 1, so that the next character appears in the display unit to the right. Auto increment right entry let character to be displayed in electronic calculators form. It is reason for the display to be shifted left to 1 character and stores the next character from the right.
Addressing mode of 8086 : Addressing mode specify a way of locating operands or data. Depending on the data types used the memory addressing modes and in the instruction ,
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Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
Entering a Program In this section, we will explain the procedure for entering a small program on IBM PC with DOS operating system. Assume a program of addition of 2 bytes, as
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Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Assembly Language Example Programs We studied the entire instruction set of 8086/88, pseudo-ops and assembler directives. We have explained the process of entering an assembly
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Software Interrupts Software interrupts are the result of an INT instruction in an executed program. It may be assumed as a programmer triggered event that immediately stops e
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