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Display control
8279 provides a 16 byte display memory and refresh logic. Every address in the display memory corresponds to a display unit with address zero representing the leftmost display unit. Output is accomplished by 8279 again and again sending out characters over the lines OUT A3-A0 and OUT B3-B0 and unit chooses address is over SL3-SL0.
For the auto increment left entry, after every writes to the display the addresses incremented by 1, so that the next character appears in the display unit to the right. Auto increment right entry let character to be displayed in electronic calculators form. It is reason for the display to be shifted left to 1 character and stores the next character from the right.
Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)
BINARY TO GRAY CONVERSION
program to accept 23 students name using while loop let your variable control the value negative 4
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
Multiply two numbers by using shift and rotate instruction
Trying to convert small programs from C to 8086 assembly language using emu 8086 emulator. I converted to low level C, but struggling with converting to the Assembly language.
Write a program that defines symbolic constants for all of the days of the week
XOR: Logical Exclusive OR: The XOR operation is again carried out in a similar way to the AND and OR operation. The constraint over operands are also similar. The XOR operation pr
The modes are determined by the contents of the control register, whose format is given in Figure These modes are: Mode 0: If a group is in mode 0, it is divided into 2 sets.
segmentation and overlapping in assemble language
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