Discover the suitable diameter of the shaft, Mechanical Engineering

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Discover the suitable diameter of the shaft:

A shaft is required to fail while the torque on the shaft is 20 kN-m. Discover the suitable diameter of the shaft of the modulus of rupture of torsion is 200 mN/m2.

 Solution

T = 200 kN-m = 20 × 103 N-m

τmax = 200 MN/m2 = 200 × 106 N/m2

d = ?

τmax      = 16T /πd3

⇒200 × 106  = 16 × 20 × 10/ πd 3

∴ d = 7.99 × 10- 2 m = 80 mm


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