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Discover the maximum torque:
Discover the maximum torque that may be transmitted by the shaft of 400 mm diameter, if the shear stress is not to exceed 50 N/mm2.
Solution
τmax = 50 N/mm2 = 50 × 106 N/m2, d = 400 mm = 0.4 m
τmax = 16T/ πd3
⇒ 50 × 106 = 16 × T / (π (0.4)3)
∴ T = 628.3 × 103 Nm = 628.5 Nm
deff. b/w asa and ors
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