Diffraction by solids, Chemistry

Assignment Help:

DIFFRACTION BY SOLIDS

Diffraction performs when a wave interacts with a lattice whose dimensions are of the same order of magnitude as that of the wavelength of the waves. The lattice scatters the radiation, and the scattered radiation from one point interferes with the radiation from others so as to either reduce it (destructive interference), or enhance the amplitude of the radiation (constructive interference). The pattern of destructive and constructive interference yields information about molecular and crystal structure.

1228_diffraction by solid.png

 

Fig.1. Constructive (a) and destructive (b) interference of two

waves.

In the case of solids, this wavelength must be of the same order as the crystal lattice spacing (ca. 0.1nm), and there are three primary types of radiation which are used for structural studies of solids. The most commonly used radiation, X-rays, have wavelengths of the order of 0.15 nm, and in the course of diffraction studies are scattered by the electron density of the molecule.


Related Discussions:- Diffraction by solids

Electrovalent bond formation depends on, Electrovalent bond formation depen...

Electrovalent bond formation depends on: (1) Ionization energy (2) Electron affinity (3) Lattice energy (4) All the three above Ans:  All the three above

Borazine, Reaction of ammonia with diborane at 475K gives a compound B3N3H6...

Reaction of ammonia with diborane at 475K gives a compound B3N3H6 known as borazine or borazole: Borazine is best prepared by reducing B-trichloroborazme with sodium borohy

Radioanalytical methods, Radioanalytical methods: Radioanalytical meth...

Radioanalytical methods: Radioanalytical methods using radiotracers and activation analysis are more sensitive and specific because of ease of detection of nuclear radiation.

Entropy, definition for entropy?

definition for entropy?

Extensive chemistry of the boron hydrides, Q. Extensive chemistry of the bo...

Q. Extensive chemistry of the boron hydrides? The extensive chemistry of the boron hydrides finds no parallel with the hydrides of heavier elements of Group 13. Out of the four

Equilibrium equations, 2NO N2 + O2 has a Keq of 85 Keq = [N2}{02} ...

2NO N2 + O2 has a Keq of 85 Keq = [N2}{02} ------- [NO]2 at equilibrium, would have more reactants or products

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd