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Differentiate following functions.
(a) f ( x ) = 2 x5 cosh x
(b) h (t ) = sinh t / t + 1
Solution
(a) f ′ ( x ) = 10x4 cosh x + 2x5 sinh x
(b) h′ (t ) = (t + 1) cosh t - sinh t /(t + 1)2
The actual solution is the specific solution to a differential equation which not only satisfies the differential equation, although also satisfies the specified initial conditions
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i dont understand what my teacher disccussing thats why i want to learn for this lesson. i want to ask'' what is the variables?
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