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Differentiate following functions.
(a) f ( x ) = 2 x5 cosh x
(b) h (t ) = sinh t / t + 1
Solution
(a) f ′ ( x ) = 10x4 cosh x + 2x5 sinh x
(b) h′ (t ) = (t + 1) cosh t - sinh t /(t + 1)2
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why this kolavari di?
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