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Differentiate following functions.
(a) f ( x ) = 2 x5 cosh x
(b) h (t ) = sinh t / t + 1
Solution
(a) f ′ ( x ) = 10x4 cosh x + 2x5 sinh x
(b) h′ (t ) = (t + 1) cosh t - sinh t /(t + 1)2
Find out the area of the region bounded by y = 2 x 2 + 10 and y = 4 x + 16 . Solution In this case the intersection points (that we'll required eventually) are not going t
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solve and graph the solution set 7x-4 > 5x + 0
Components of the Vector We should indicate that vectors are not restricted to two dimensional (2D) or three dimensional space (3D). Vectors can exist generally n-dimensional s
project on shares and dividends
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y''''+6y''+10y=10x^(4)+24x^(3)+2x^(2)-12x+18
int*sin^-1 x dx=?
how do you round to the nearest dollars?
suresh invested rs.1080 in shares of face value rs.50 at rs.54.After receiving dividend on them at 8% he sold them at 52.In each of the transaction he paid 2 % brokerage.Hpw much d
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