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Differences of Squares (and other even powers) ?
A square monomial is a monomial which is the square of another monomial. Here are some examples:25 is the square of 5x2 is the square of xx4y6 is the square of x2y325x4y6 is the square of 5x2y3
How do you know if a monomial is a square? It's easy. It's a square if
1. the coefficient is a perfect square (which, by the way, means it can't be negative) and 2. all the exponents on the variables are even.
Remember that the word difference means subtraction. So here's an example of a difference of squares: 25 - 4x2.(Notice that 25 is a perfect square, and so is 4x2.)Factoring a difference of squares is easy.
Step 1: Rewrite the two terms as squares of something.25 - 4x2= 52 - (2x)2 Step 2: Apply the rule a2 - b2 = (a -b )(a + b).
= (5 -2x)(5 + 2x)
Use Newton's Method to find out an approximation to the solution to cos x = x which lies in the interval [0,2]. Determine the approximation to six decimal places. Solution
1. Sketch the Spiral of Archimedes: r= aθ (a>0) ? 2: Sketch the hyperbolic Spiral: rθ = a (a>0) ? 3: Sketch the equiangular spiral: r=ae θ (a>0) ?
The probability that a certain region in mexico will be hit by a hurricane in any given year is .06. What is the probability that the region will be hit by at least one hurricane i
the variables x and y are thought to be related by a law of the form ay^2=(x+b)lnx Where a and b are unknown constants. Can a and b be found and how.
How we calculate region for curve tracing
Solve 5x tan (8x ) =3x . Solution : Firstly, before we even begin solving we have to make one thing clear. DO NOT CANCEL AN x FROM BOTH SIDES!!! Whereas this may appear like
A telephone exchange has two long distance operators.The telephone company find that during the peak load,long distance calls arrive in a poisson fashion at an average rate of 15 p
what is the factor of the trinomial 2x2-7x-4
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can b
sin (cot -1 {cos (tan -1 x)}) tan -1 x = A => tan A =x sec A = √(1+x 2 ) ==> cos A = 1/√(1+x 2 ) so A = cos -1 (1/√(1+x 2 )) sin (cot -1 {cos (tan -1 x)}) = s
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