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Difference between the fork -join and begin-end.
The fork - join keywords:
Groups several statements together.Cause statements to be evaluated in parallel (all at the same time).
-> Timing within parallel group is absolute to beginning of the group.
-> Block finishes after the last statement completes (Statement with highest delay, it can be the first statement in the block).
Explain segmentation? Segment memory addressing divides memory into many segments. Each of these segments can be considered as a linear memory space. Every one of these segmen
What do you understand by stepwise refinement of the program? The method of "Stepwise refinement" means to take an object and move it from a general perspective to a exact leve
Rounding off of values can be carried out using the write statement. Yes, Rounding off value can be out by using the write statement.
What is SEGMENT - Assembler directives SEGMENT: This directive defines to assembler the start of a segment with name segment-name. Segment name must be unique and follows the
Explain Sequential Sharing In this sharing method, a file can be shared by just one program at a time, i.e. file accesses by P1 and P2 are spaced out over time. A lock field ca
Define a console-program to make an array of integers. Initialize the array and assign the values in array. Describe a method to pass the array and alter array elements. show array
Illustrate the following list of consideration of laptop computers The following is a list for consideration: - The processor must consume as little power as possible thus
a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be foun
What is the use of the statement Leave to List-processing? Leave to List-processing statement is used to make a list from a module pool. Leave to list processing statement per
What is divide overflow? The division operation might result in a quotient with an overflow. Overflow happens when the length of the registers is finite and will not hold a nu
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