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Question (a) A CRC is constructed to generate a 4-bit FCS for an 11-bit message. The divisor polynomial is X4 + X3 + 1
(i) Encode the data bit sequence 00111011001 using polynomial division and give the code word.
(ii) Assume that 7th MSB in the data bit sequence above gets corrupted during transmission, show how the detection algorithm detects the error.
Question (b) What is the difference between Synchronous TDM and Statistical TDM?
(c) In respect to HDLC:
(i) State the three data transfer modes of operation.(ii) Give the structure of generic HDLC frame.(iii) Explain why HDLC uses 'bit stuffing'.
Question (d) With the aid of sketches, explain the difference between the following two transmission modes used with optical fibre:
(i) Graded-index Multi-mode and
(ii) Mono-mode.
IPV6 NEXT HEADER It is given in the figure below:
FRAGMENTATION One method is to limit datagram size to smallest MTU of any server. IP needs fragmentation i.e. datagrams can be divided into pieces to fit in network with small
B-Router Hybrid devices that has the features of both routers and bridges . A bridge router or brouter is a network machine that acts as a router and as a bridge. The brout
QUESTION (a) A convex flow problem is a non linear network flow problem. Explain how a convex flow problem could be transformed into a Minimum Cost Flow problem. (b) Exp
attacks on crytography
ADDRESS RESOLUTION WITH TABLE LOOKUP : Resolution needs data structure that has information about address binding. A distinct address-binding table is used for every physical n
Incident Response: Complete the following sections as identified from your Incident Response template (in MS Word format): Update the table of contents (autogenerated) Separate
ADDRESS RESOLUTION WITH MESSAGE EXCHANGE An alternative to local calculation is a distributed function. A computer that requires to find an address transmits a message across
Question requires you to develop firewall rules based on a fictitious organisation. Scenario: You work for a security-conscious company, xC-Cure, who develop encryption te
FRAGMENTATION AND PATH MTU IPv6 source is responsible for fragmentation. Routers simply drop datagrams bigger than network MTU. So source have to fragment datagram to arrive d
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