Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
A 0.500 kg stone attached to the end of a string is whirled in a vertical circle of radius 1,20 meters. The center of the vertical circle is 1.50 meters above the ground. When the stone is at the top of the circle, the tension in the string is 1.80 N. If the string is released at that point, where does the stone hit the ground? In other hand, what are the x and y coordinates of the position where the stone hits the ground? Note: place the origin of your coordinate system at the center of the vertical circle.
PHYSICS ELECTRICITY EXPERIMENT - TO VERIFY OHM'S LAW WITH THE HELP OF AMMETER AND A VOLTMETER. 1. Procedure for the storage of equipment used in the experiment. Enquir
An experiment with two spikes Use the drill for a rotation machine as in the above experiment. Unite two spikes by attaching the point end of every to the end of a 15 cm length
A bat emits a sound whose frequency is 142 kHz. The speed of sound in air at 20.0°C is 343 m/s. However, the air temperature is 35°C, so the speed of sound is not 343 m/s. Find the
It is an instrument used to view pure spectrum. It makes dispersion without deviation with the help of n crown prisms and (n - 1½ flint prisms alternately arranged in a tabular str
Explain Scalars and Vectors This is one of the harder ideas to get used to when you start learning physics. The trick is to see that there is one basic difference between a sca
a glass prism in the shape of a quaeter-cylinder lies on the table.a uniform,horizontal light falls on its vertical plane surface,as shown in the figure.if the radius of the cylind
what does it mean
Ohm's law (G. Ohm; 1827): The ratio of the potential difference among the ends of a conductor to the current passing through it is constant; the constant of proportionality is
a pendulum is timed ,first for 20 swings and then for 50 swings ; time for 20 swings = 17.4 sec and time for 50 sec = 43.2. calculate the average time per swing/
To an order of magnitude, how many helium-filled toy balloons would be needed to lift you off the ground? Helium is an irreplaceable resource so make a theoretical solution rather
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd