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Solve following equations.
1/(x+1) = 1- (5/2x - 4)
Solution
Just like along with the linear equations the primary thing which we're going to need to do here is to clear the denominators out through multiplying by the LCD. Remember that we will also have to note value(s) of x which will give division by zero so that we can ensure that these aren't involved in the solution.
1/ (x+1) = 1 - (5/2x - 4)
The LCD for this problem is ( x + 1)(2x - 4) and we will have to avoid x =-1 and x = 2 to ensure we don't get division by zero. Following is the work for this equation.
( x + 1) ( 2x - 4) (1/(x+1))= (x + 1) ( 2 x - 4) (1 - 5/2x - 4)
2x - 4 = ( x + 1) ( 2 x - 4) - 5 ( x + 1)
2x - 4 =2 x2 - 2 x - 4 - 5x - 5
0 = 2x2 - 9x - 5
0 = ( 2x + 1) ( x - 5)
Thus, it seem like the two solutions to this equation are following,
x =- 1/2 and x = 5
Notice that neither of these are the values of x which we needed to avoid nor so both are solutions.
1.Ms. Nioka and seven of her friends went out to eat. They decided to split the bill evenly. each person paid $8.73. What was the total bill.
3x/4 = 2
I need help with complex fractions
The sum of 4 consecutive integers is 130. what are the four integers?
how do you work it out?
Determine which system below will produce infinitely many solutions. 2x + 5y = 24 2x + 5y = 42 3x - 2y = 15 6x + 5y = 11 4x - 3y = 9 -8x + 6y = -18 5x - 3y = 16 -2x + 3y =
f(-4)=-2-4=3
7a + 6b = 14 -7a + b =35 solve by the elimination method
Now, let's solve out some double inequalities. The procedure here is alike in some ways to solving single inequalities and still very different in other ways. As there are two ineq
Do you have any helpful hints for solving equations?
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