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Determine the Projection of b = (2, 1, -1) onto a = (1, 0, -2)
There is a requirement of a dot product and the magnitude of a.
a→ • b→ = 4 ||a→||2 = 5
the projection is then,
Proja? b→ = a→• b→ / (||a→||2) (a→)
= 4/5 (1, 0, -2)
= (4/5,0,- 8/5)
sin (cot -1 {cos (tan -1 x)}) tan -1 x = A => tan A =x sec A = √(1+x 2 ) ==> cos A = 1/√(1+x 2 ) so A = cos -1 (1/√(1+x 2 )) sin (cot -1 {cos (tan -1 x)}) = s
The angles between three non-zero and non coplanar vectors a,b and c are α between b and c and β between c and a and γ between a and b. The vector u and v are defined by u=(aX
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#question.x2-y2-4x-2y+3.
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