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The scores of students taking the ACT college entrance examination are normally distributed with a mean m = 20.1 and a standard deviation s = 5.8.
A single student is selected at random. Determine the probability that their ACT score was between 18 and 24.
a) Determine the probability that a simple random sample of 25 students would earn an average score of at least 22.
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If the roots of the equation (a-b) x 2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c. Ans: (a-b) x 2 + (b-c) x+ (c - a) = 0 T.P 2a = b + c B 2 - 4AC = 0
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