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Q. In a differentiating circuit, R=10 kW,and C=2.2μF.If the input voltage goes from 0V to 10 V at a constant rate in 0.4s, determine the output voltage.
Solution:
e0 = RC x d/dt(ei) = RC x dei/dt
R = 10 kW, C = 2.2μF
dei/dt = (10-0)/0.4 = 25 V/se0 = (10 x103) x (2.2 x 10-6 ) x 25 = 0.55 V
i am battling with mesh, node anaalysis, superposition, node thevenin and norton equivalents
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