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Determine the measure of the vertex angle of the isosceles triangle.
a. 34°
b. 16°
c. 58°
d. 112°
d. Simply substitute x = 34 into the equation for the vertex angle, 3x + 10. The result is 112°. If you select a, you solved for the base angle. If you select b, the original equation was written incorrectly as x + x + 3x + 10 = 90.
Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique) A=bq+r, where o ≤ r 48=18x2+12 18=12x1+6 12=6x2+0 ∴ HCF (18,48) = 6 now 6
Andy earned the subsequent grades on his four math quizzes: 97, 78, 84, and 86. What is the average of his four quiz grades? To ?nd out the average, you must add the items (97
I dont understand arcsin and arccos and how to find the domain...help?
In the figure, ABCD is a square inside a circle with centre O. The Centre of the square coincides with O & the diagonal AC is horizontal of AP, DQ are vertical & AP = 45 cm, DQ = 2
If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region. (Ans:21cm 2 ) Ans: Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2 x 14 x
How can I solve simultaneous equations?
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Evaluate following limits. Solution Therefore we will taking a look at a couple of one-sided limits in addition to the normal limit here. In all three cases notice
From an aero plane vertically above a straight horizontal road, the angles of depression of two consecutive milestones on opposite sides of the aero plane are observed
the radii of circular base of right circular cylinder and cone are in the ratio of 3:4 and their height are in the ratio of the 2:3 what is the ratio of their volume?
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