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Given f (x) = - x2 + 6 x -11 determine each of the following.
(a) f ( 2)
(b) f ( -10)
(c) f (t )
Solution
(a) f ( 2) = - ( 2)2 + 6(2) -11 = -3
(b) f ( -10) = - ( -10)2 + 6 ( -10) -11 = -100 - 60 -11 ) -171
Be careful while squaring negative numbers!
(c ) f (t ) = -t 2 + 6t -11
Recall that we substitute for the x's whatever is in the parenthesis on the left. Frequently this will be something other than a number. Thus, in this case we put t's into for all the x's on the left.
Tangents with Parametric Equations In this part we want to find out the tangent lines to the parametric equations given by X= f (t) Y = g (t) To do this let's first r
i need somehelp i am not the sharpest in the pack so plz help me thank you i hope you do
f(x)+f(x+1/2) =1 f(x)=1-f(x+1/2) 0∫2f(x)dx=0∫21-f(x+1/2)dx 0∫2f(x)dx=2-0∫2f(x+1/2)dx take (x+1/2)=v dx=dv 0∫2f(v)dv=2-0∫2f(v)dv 2(0∫2f(v)dv)=2 0∫2f(v)dv=1 0∫2f(x)dx=1
how to find
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