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Q. Consider a pair of coupled coils as shown in Figure of the text, with currents, voltages, and polarity dots as indicated. Show that the mutual inductance is L12 = L21 = M by following these steps:
(a) Starting at time t0 with i1(t0) = i2(t0) = 0, maintain i2 = 0 and increase i1 until, at time t1, i1(t1) = I1 and i2(t1) = 0. Determine the energy accumulated during this time. Now maintaining i1 = I1, increase i2 until at time t2, i2(t2) = I2. Find the corresponding energy accumulated and the total energy stored at time t2.
(b) Repeat the process in the reverse order, allowing the currents to reach their ?nal values. Compare the expressions obtained for the total energy stored and obtain the desired result.
Transmission Through a LiNb0 3 Plate Examine the transmission of an unpolarized He-Ne laser beam (?o= 633 nm) normally incident on a LiNb0 3 plate (ne = 2.29, no = 2.20) of thickn
Time constant Time constant, defines as time for current achieve maximum (IM) if this maintain the early promotion rate current.
In second technique, a concentrator expander (CE) is used near cluster of users and another one at exchange end as demonstrated in figure. Only a few junction lines are run between
Q. J and K are the external inputs to the JKFF shown in Figure. Note that gates 1 and 2 are enabled only when the clock pulse is high. Consider the four cases of operation and expl
what is bias compensation
We have seen that a practical power source may be modelled by an ideal constant voltage source in series with a resistor - a Thevenin equivalent circuit Alternati
Q. Three loads in parallel are supplied by a single phase 400-V, 60-Hz supply: Load A: 10 kVA at 0.8 leading power factor Load B: 15 kW at 0.6 lagging power factor Load C:
ON output plot of a JFET n-channel transistor if ID is close to IDSS does the value of VGS close to VP?
Q. What do you mean by Time consistent Busy Hour? (i) Busy Hour (ii) Peak Busy Hour (iv) Time consistent Busy Hour (v) Traffic intensity Ans: (i) Busy Hour: C
Q. For a transistor, when v GS = -2.0 V, find V DSsat if Vp= -4.0 V for an n-channel depletion mode MOSFET. Solution: V p = -(V DSsat + v SG ) but v SG = -v GS = -(-
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