Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Determine the dead load:
A 250 mm diameter sewer is placed in a 2.75 m deep rectangular trench that is 0.65 m wide. This trench is backfilled with saturated clay having a unit weight of 20.4-kN/m3. Determine the dead load due to the backfill that the sewer must support. What class of bedding is to be specified if the crushing strength of this pipe is 23.2 kN/m, and the value of safety factor to be used is 1.5?
Solution
Here, H = 2.75 m - 0.25 m
= 2.50 m
∴ H/B = 3.85
From Figure 6.16, we read C = 2.65
We have W = 2.65 × 20.4 × (0.65)2 = 22.84 kN/m
Safe Supporting Strength = (Load Factor × Crushing Strength)/Safety Factor
Load factor = 1.48
Therefore, we specify Class C bedding for the given sewer line.
Write down the maintenance schedule for the following : (a) Spark plug replacement. (b) Engine oil change/ top up period. (c) Steering head bearing.
Sum of horizontal and vertical components: The two forces shown in the figure, are to be replaced by an equivalent force R applied at P . Locate point P by finding its d
Need a basic explanation of how to go about doing a plane strain analysis of a pressure vessel
parameters specified in a steam boiler
Hodgkin-Huxley Fast Subsystem 1. Explain why replacing the extracellular Na + with choline has little effect on the resting potential of an axon. Calculate the new resting po
how is the downward force is Mg+S*()
Exhaust Manifold : The pipe which connects the exhaust system to the exhaust valve of the engine through which the products of combustion escape into the atmosphere is called the
During the test run of prototype machine we found out a few issue occurred due to blasting room design problem. The blasting room design is too quartet, this design had cause the b
What is one way shear? Explain with a suitable demonstration. One Way Shear This worked out seen a similar case is the case of wall footings. For square footings also the cr
Arc strikes Represent any localised heat affected zone caused by an arc. Arc strike tends to produce hardening particularly in high carbon steels and alloy steels. Grinding of
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd