Assume that the amount of money in a bank account after t years is specified by,
![901_extrema.png](https://www.expertsmind.com/CMSImages/901_extrema.png)
Find out the minimum & maximum amount of money in the account throughout the first 10 years that it is open.
Solution: Here we are actually asking for the absolute extrema of A(t) within the interval [0,10]. As with the earlier examples this function is continuous everywhere and thus we know that this can be done.
First we'll require the derivative thus we can determine the critical points.
![640_extrema1.png](https://www.expertsmind.com/CMSImages/640_extrema1.png)
The derivative presents everywhere and the exponential is never zero. So the derivative will only be zero where,
-1 + (t2/4) = 0 ⇒ t 2 = 4 ⇒ t = ±2
We've obtained two critical points, however only t = 2 is in fact in the interval so that is just critical point that we'll utilizes.
Now let's evaluate the function at the lone critical point & the end points of the interval. Following are those function evaluations.
A (0) = 2000 A ( 2) = 199.66 A (10) = 1999.94
Thus, the maximum amount in the account will be $2000 that takes places at t = 0 and the minimum amount in the account will be $199.66 that occurs at the 2 year mark.