Determine the axial strength of the plates in direct tension, Civil Engineering

Assignment Help:

The two plates shown below are each 10-in. wide by ¾- in. thick. The gage distance, g, and the longitudinal spacing on each member is set at 4-in. Determine the axial strength of the plates in direct tension. Assume grade 36 steel (Fy = 36 ksi, Fu = 58 ksi). The bolts used are ¾-in.

637_Determine the axial strength of the plates in direct tension.png

A) 322 kip

B) 273 kip

C) 416 kip

D) 243 kip

Related Discussions:- Determine the axial strength of the plates in direct tension

Determine the station and elevation of turning point, A -3.00% grade inters...

A -3.00% grade intersects a +1.25% grade at Sta. 85+80 and elevation 210.00 ft. A 350-ft vertical curve connects the two grades. Determine the station and elevation of turning po

Helical reinforcement designed instead of regular links, Question For colum...

Question For column reinforcements, why is helical reinforcement sometimes designed instead of regular links with reasons? Answer The utilization of links for column designi

Two property rule , The state of a pure substance of given mass is defined ...

The state of a pure substance of given mass is defined by specifying two appropriate properties provided that 1. The system is in equilibrium 2. Gravity, motion, electricity,

Classification of timber based on modulus of elasticity, Classification Bas...

Classification Based on Modulus of Elasticity: Young's modulus is resolute by conducting bending test. On this basis timber is classified as following: Group A: E = 12.5 kN

Strength of material, Shear stress in rectangular section formula

Shear stress in rectangular section formula

Cement, Why we mixm pozzolona in cement

Why we mixm pozzolona in cement

Distomat., short note

short note

Surface drainage, Surface Drainage: Surface drainage deals with arran...

Surface Drainage: Surface drainage deals with arrangement for quickly leading the water from rainfall away from the surface of pavements, shoulders, slopes of embankments and

Reciprocal ranging, what do you mean by reciprocal ranging explain with a n...

what do you mean by reciprocal ranging explain with a neat sketch

Define design aspects of pot bearing, Define Design Aspects of Pot Bearing?...

Define Design Aspects of Pot Bearing? Basic elements of a POT bearing are: - POT or a shallow cylinder - An elastomeric pad - A set of sealing rings - A piston P

6/1/2013 2:23:01 AM Answer: Gross Yielding: φTn= 0.9036 ksi 10-in. * 0.75-in. = 243 kip Net fracture: There are three possible failure modes for the net section: For failure mode 1, the net section is: A_n = (10-in. - 2(13/16-in.))0.75-in = 6.28 in² For failure mode 2 and 3, the net section is: A_n = (10-in. - 3(13/16-in.)+2((4-in)²/(44-in.))0.75-in = 9.5625 in² The smallest area will govern, so failure mode 1 will be the lowest: φTn = 0.7558 ksi 6.28in2 = 273 kip Thus, the gross section is lower, the answer is 243 kips.

6/1/2013 2:23:01 AM

Answer:

Gross Yielding:

φTn= 0.90*36 ksi * 10-in. * 0.75-in. = 243 kip

Net fracture:

There are three possible failure modes for the net section:

For failure mode 1, the net section is:

A_n = (10-in. - 2*(13/16-in.))*0.75-in = 6.28 in²

For failure mode 2 and 3, the net section is:

A_n = (10-in. - 3*(13/16-in.)+2*((4-in)²/(4*4-in.))*0.75-in = 9.5625 in²

The smallest area will govern, so failure mode 1 will be the lowest:

φTn = 0.75*58 ksi * 6.28in2 = 273 kip

Thus, the gross section is lower, the answer is 243 kips.

Write Your Message!

Name

Email id

Message

Verfication Code

User Account

All Pages