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1) At a midway game at the state fair, the probability of winning an individual game is advertised to be 30% (p = . 3). Suppose 50 people played the game (assume all 50 outcomes are independent).
a) Determine the probability that exactly 15 of the 50 people win.
b) Determine the probability that between 12 and 14 people win (i.e. at least 12 but no more than 14 win).
c) What is the average number (expected number) of winners?
41x + 53y = 135, 53x +41y =147 Ans: 41x + 53 y = 135, 53 x + 41 y = 147 Add the two equations : Solve it, to get ... x + y = 3 -------(1) Subtract : Solve it , to
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