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Three equal weights A, B, C of mass 2 kg each are hanging on a string passing over a fixed frictionless pulley as shown. Tension in the string connecting weights B and C is approximately.
Answers: Acceleration of the system = a = (4-2)g/4+2
i.e. a=g/3
Tension in the string between B and C
T= apparent weight of C
= 2(g-a)
= 2(g-g/3)
= 13.07N
why the least distance of distinct vision is 25 %
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