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Three equal weights A, B, C of mass 2 kg each are hanging on a string passing over a fixed frictionless pulley as shown. Tension in the string connecting weights B and C is approximately.
Answers: Acceleration of the system = a = (4-2)g/4+2
i.e. a=g/3
Tension in the string between B and C
T= apparent weight of C
= 2(g-a)
= 2(g-g/3)
= 13.07N
The resultant of two forces 3P and 2P is R. If the first force is doubled then the resultant is also doubled. then the angle between the two forces us. plz xplain with the solution
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