Determine resources, need matrix using banker's algorithm, Computer Engineering

Assignment Help:

Consider the following system snapshot using data structures in the Banker's algorithm, with resources A, B, C, and D, and process P0 to P4:

                          Max                             Allocation                        Need                             Available

 

P0

A

6

B

0

C

1

D

2

A

4

B

0

C

0

D

1

A    B   C   D

A

B

C   D

P1

1

7

5

0

1

1

0

0

 

 

 

 

P2

2

3

5

6

1

2

5

4

 

 

 

 

P3

1

6

5

3

0

6

3

3

 

 

 

 

P4

1

6

5

6

0

2

1

2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

3

2

1    1

Using Banker's algorithm, answer the following questions.

(a)   How many resources of type A, B, C, and D are there?

(b)   What are the contents of the Need matrix?

(c)   Is the system in a safe state? Why

(d)  If a request from process P4 arrives for additional resources of (1,2,0,0,), can  the  Banker's  algorithm  grant  the  request  immediately? Show the new system state and other criteria.

(a) Resources of type A, B, C, and D are as: A-9; B-13;C-10;D-11

(b) Need[i, j]=Max[i,j]-Allocation[i,j] therefore content of Need matrix is

            A          B          C          D

P0        2          0          1          1

P1        0          6          5          0

P2        1          1          0          2

P3        1          0          2          0

P4        1          4          4          4

(c)  The  system  is  in  a  safe  state  like  the  processes  can  be  complete  in  the sequence P0, P2, P4, P1 and P3.

(d) If a request from process P4 attains for additional resources of (1,2,0,0,), and if such request is granted so the new system state would be in tabulated form asfollows.

                  Max                    Allocation              Need                         Available

             A   B   C    D        A   B   C   D              A   B    C    D               A   B   C   D

P0        6    0    1    2         4    0    0    1          2    0    1    1

P1        1    7    5    0         1    1    0    0          0    6    5    0

P2        2    3    5    6         1    2    5    4          1    1    0    2

P3        1    6    5    3         0    6    3    3          1    0    2    0

P4        1    6    5    6         1    4    1    2          0    2    4    4

2    0    1    1

After PO finishes P3 can be assigned. 1020 from released 6012 and also available 2011(Total 80 23) and is a safe sequence.


Related Discussions:- Determine resources, need matrix using banker's algorithm

4bit counter using JK flip flop and unique sequence, Need to build a 4bit J...

Need to build a 4bit JK flip flop counter with a unique patter. 6 4 2 5 3 1 F C B A

Illustrate the working of flip-flops, Q. Illustrate the working of FLIP-FLO...

Q. Illustrate the working of FLIP-FLOPS? A flip-flop is a binary cell that stores 1-bit of information. It itself is a sequential circuit. We know that flip-flop can change its

Queueing process, explain in detail about queueing process

explain in detail about queueing process

What is a scope resolution operator, A scope resolution operator (::), can ...

A scope resolution operator (::), can be used to describe the member functions of a class outside the class.

Explain the quantization error of an ADC, Explain the Quantization error...

Explain the Quantization error of an ADC. Ans. Quantization error- An analog voltage is within the range of 0 to 1V and for 3 bit output, the size of all intervals are

Classify process and differentiate program, Classify Process, differentiate...

Classify Process, differentiate program, process A process maybe concerned to be a program being run. A program isn't a process of itself; it's a passive Entity while the proce

Interrupt and scanning method of keypad operation, INTERRUPT METHOD - USING...

INTERRUPT METHOD - USING PORTB CHANGE INTERRUPT By using 4 by 4 matrix keypad connected to PORTA and PORTB. The rows are connected to PORTA-Low (RA1-RA4) and the columns are co

Advantage and disadvantage of threaded binary trees, Advantage  1.     ...

Advantage  1.       By doing threading we neglect the recursive method of traversing a Tree , which makes use of stack and consumes many memory and time . 2.       The node

How much CMOS circuits consume power, CMOS circuits consume power ? An...

CMOS circuits consume power ? Ans. As in CMOS one device is ON and one is Always OFF therefore power consumption is low or can say less than TTL.

Combinational logic, At a particular moment in time the output of a COMBINA...

At a particular moment in time the output of a COMBINATIONAL logic circuit depends uponthe inputs to the circuit at the same instant.(Unlike sequential logic circuits where the out

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd