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Q. In an amplifier, the maximum voltage gain is 1500 and occurs at 1kHz. It falls to 1060.5 at 20kHz and at 20Hz. Determine
(i) lower cut-off frequency
(ii) upper cut-off frequency and
(iii) bandwidth.
Maximum gain = 1500 x% of 1500 = 1060.5
Thus, x = 70.7%
(i) Lower cut-off frequency = f1 = 20Hz
(ii) Upper cut-off frequency = f2 = 20kHz
(iii) Bandwidth = f2-f1 = 19.98kHz
make the following conversion 1000 Mx to Wb
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