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Determine currents in the circuits:
Determine currents I1 and I2 in the given circuits by applying KVL.
Solution
We apply KVL for first loop :
10 = 1 I1 + 1 ( I1 - I 2 )
10 = 2 I1 - I 2 ---------- (i)
KVL for second loop :
1 ( I 2 - I1 ) + 4 I 2 = 0
5 I 2 - I1 = 0 --------- (ii)
∴ I2 = I1 /5 = 0.2 I1 --------- (iii)
Put the value of I2 in Eq. (i)
10 = 2 I1 - 0.2 I1 = 1.8 I1
⇒ I1 = 5.55 Amp
From Eq. (iii), I2 = 1.11 Amp .
There are total 12 interrupts in 8085.
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