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A certain memory has a capacity of 4K × 8(i) How many data input and data output lines does it have?(ii) How many address lines does it have?(iii) What is its capacity in bytes?Ans.
(i) available capacity =4Kx8= 210 x210 x 8= 212x8Since in the 4Kx8 ,the second number shows the number of bits in each word therefore the number of data input lines will be 8 and also the data output lines.(ii) That has total 4K (212) address line that are required to address 212 locations.(iii) Capacity in bytes of this is 4K bytes.
Sample Program In this program we only display: Line Offset Numbers -----------------Source Code-----------------
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i want program code for the above question in c language
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