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Remember that a graph will have a y-intercept at the point (0, f (0)) . Though, in this case we have to ignore x = 0 and thus this graph will never cross the y-axis. It does get extremely close to the y-axis, but it will never cross or touch it & thus no y-intercept.
Next, remember that we can determine where a graph will have x-intercepts by solving f ( x ) = 0 .
For rational functions this might seem like a mess to deal along with. Though, there is a nice fact regarding rational functions which we can use here. A rational function will be zero at a specific value of x only if the numerator is zero at that x & the denominator isn't zero at that x. In other terms, to determine if a rational function is ever zero all that we need to do is set the numerator equal to zero & solve. Once we have these solutions we just need to check that none of them make the denominator zero as well.
In our case the numerator is one and will never be zero and so this function will have no x- intercepts. Again, the graph will get extremely close to the x-axis but it will never touch or cross it.
At last, we have to address the fact that graph gets extremely close to the x and y-axis but never crosses. Since there isn't anything special about the axis themselves we'll use the fact that the x- axis is actually the line specified by y =0 and the y-axis is really the line specified by x = 0.
(14,20) and (-15,3)
the table shows the number of minutes of excirccise for each person compare and contrast the measures of variation for both weeks
9x-2y=3
It is the final type of problems which we'll be looking at in this section. We are going to be looking at mixing solutions of distinct percentages to obtain a new percentage. The
Here we'll be doing is solving equations which have more than one variable in them. The procedure that we'll be going through here is very alike to solving linear equations that i
How much of a 50% alcohol solution should we mix with 10 gallons of a 35% solution to get a 40% solution? Solution Let x is the amount of 50% solution which we need. It me
Solve 2 x 10 - x 5 - 4 = 0 . Solution We can reduce this to quadratic in form using the substitution, u = x 5 u 2 = x 10 By using this substitution the equa
Now we need to discuss the new method of combining functions. The new way of combining functions is called function composition. Following is the definition. Given two functions
5(8-2t)
solve each equation for given variable 3ab-2bc=12;
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