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Q. An, array, A comprises of n unique integers from the range x to y(x and y inclusive where n=y-x). Which means, there is only one member that is not in A. Design an O(n) time algorithm to find that number.
Ans:
The algorithm to find the number that is not array A where n contains n
unique (n = x - y):
find(int A[],n,x,y)
{
int i,missing_num,S[n]; for(i=0, i {if(S[i] == -999) { missing_num = i + x; break; } } }
{if(S[i] == -999)
missing_num = i + x;
break;
}
for i=1 to n if a[i}>7 for j=2 to n a[j]=a{j}+j for n=2 to n a[k]=a[j]+i else if a[1]>4 && a[1] for 2 to a[1] a[j]= a{j]+5 else for 2to n a[j]=a[j]+i ..
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