Design a mod-6 synchronous counter, Computer Engineering

Assignment Help:

Design a MOD-6 synchronous counter using J-K Flip-Flops.

Ans:

Design of Mod-6 Counter:  To design the Mod-6 synchronous counter, contain six counter states (that is, from 0 to 6). For this counter, the counter design table lists the three flip-flop and their states as 0 to 6 and the 6 inputs for the 3 flip-flops. The flip-flop inputs essential to step up the counter from the now to the next state is worked out along with the help of the excitation table.  The needed counter states and the J K inputs essential for counter flip- flops are specified in the counter design table demonstrated in Table no.1.

Input pulse

 

count

Counter States

 

Flip-Flop Inputs

 

A          B          C

 

JA

 

       KA

 

JB                KB

 

JC                  KC

0

0           0          0

1             X

0                 X

0                    X

1

1           0          0

X             1

1                 X

0                    X

2

0           1          0

1             X

X                 0

0                    X

3

1           1          0

X             1

X                 1

1                    X

4

0           0          1

1             X

0                 X

X                    0

5

1           0          1

X              1

0                 X

X                    1

6(0)

0           0         0

 

 

 

Table no.1: Counters Design Table for Mod-6 Counter

 Flip-Flop A:

The primary state is 0. This change to 1 after the clock pulses. Thus, JA must be 1 and KA may be 0 or 1 (that is X). In the subsequent state 1 change to 0 after the clock pulse.  Hence, JA may be 0 or 1 (that is, X) and KA must be 1.

Flip-Flop B:

The primary state is 0 and this remains unchanged after the clock pulse. Hence, JB   must be 0 and KB may be 0 or 1 (i.e. X). In the subsequent state 0 changes to 1 after the clock pulse. Hence, JB must be 1 and KB may be 0 or 1 (that is, X).

Flip-Flop C:

The primary state is 0 and this remains unchanged after the clock pulse. Hence JC must be 0 and KC may be 0 or 1 (that is, X). In the subsequent state, this remains unchanged after the clock pulse. Thus, JC must be 0 and KC may be 0 or 1 (that is, X).The JK inputs needed for such have been found with the help of the excitation table, (as in table no.1). The flip-flop input values are entered into Karnaugh maps demonstrated in Fig. a [(i), (ii), (iii), (iv), (v) and (vi)] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. As all the counter states have not been utilized, Xs (don't) are entered to denote un-utilized states. The expressions that simplified for each input have been demonstrated under each map. At last, these minimal expressions for the flip-flop inputs are utilized to draw a logic diagram for the counter demonstrated in fig.(b).

As before, the JK inputs needed for this have been found with the help of the excitation table, (as in table no.1). Such input values are entered in Karnaugh maps Fig. (a)[i to vi] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. Xs have been entered in that counter states that have not been utilized. The simplified expressions for all inputs have been demonstrated under each map and at last a logic diagram based upon these expressions is drawn and is demonstrated in fig.(b).

983_Karnaugh Maps for JA,KA,JB,KB,JC,KC.png

1325_Karnaugh Maps for JA,KA,JB,KB,JC,KC1.png

Fig.(b) Karnaugh Maps for JA,KA,JB,KB,JC,KC

1472_Logic Diagram for MOD-6 Synchronous Counter.png

Fig.(c) Logic Diagram for MOD-6 Synchronous Counter


Related Discussions:- Design a mod-6 synchronous counter

What will occur when contents of register are shifter left, What will occur...

What will occur when contents of register are shifter left, right? This is well known that into left shift all bits will be shifted left and LSB will be appended along with 0 a

What are primary keys and foreign keys, What are primary keys and foreign k...

What are primary keys and foreign keys? Primary keys are the unique identifiers for every row. They must have unique values and cannot be null. Due to their significance in rel

Explain the advantages of object oriented analysis design, Advantages of Ob...

Advantages of Object oriented analysis design The OO approach inherently makes every object a standalone component which can be reused within specific stat problem domains we

Features of read-only memory, Q. Features of read-only memory? ROMs are...

Q. Features of read-only memory? ROMs are memories on which it's not possible to write data when they are on-line to computer. They can only be read. This is reason why it is k

Determine the equivalent in octal of decimal number, Convert decimal 153 to...

Convert decimal 153 to octal. Equivalent in octal will be ? Ans. (153) 10 = (231) 8

Identify state as shifting register content to left by 1 bit, Shifting a re...

Shifting a register content to left by one bit position is equivalent to ? Ans. Multiplication by two is equivalent while shifting register content to left by one bit position.

Illustrate function of 4-input multiplexer using basic gates, Illustrate fu...

Illustrate functional diagram of digital multiplexer . Write the scheme of a 4- input multiplexer using basic gates (AND/OR/NOT) and explain its operation. Ans: Multiple

How to convert binary to octal and hexadecimal, Q. How to convert Binary to...

Q. How to convert Binary to Octal and Hexadecimal? Rules for these conversions are simple. For converting binary to octal binary number is splitted in groups of three, that are

Connector of conventional keyboard, 5-pin DIN connector: It is the conn...

5-pin DIN connector: It is the connector of conventional keyboard which have 5 pins (2 IN, 2 OUT and one ground pin) used for transfer and synchronization.

What is the ccitt standard bandwidth for speech, The CCITT standard bandwid...

The CCITT standard bandwidth for speech is: (A) 20000 Hz                                  (B) 15000 Hz (C) 7000 Hz                                    (D) 3400 Hz Ans:

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd