Design a mod-6 synchronous counter, Computer Engineering

Assignment Help:

Design a MOD-6 synchronous counter using J-K Flip-Flops.

Ans:

Design of Mod-6 Counter:  To design the Mod-6 synchronous counter, contain six counter states (that is, from 0 to 6). For this counter, the counter design table lists the three flip-flop and their states as 0 to 6 and the 6 inputs for the 3 flip-flops. The flip-flop inputs essential to step up the counter from the now to the next state is worked out along with the help of the excitation table.  The needed counter states and the J K inputs essential for counter flip- flops are specified in the counter design table demonstrated in Table no.1.

Input pulse

 

count

Counter States

 

Flip-Flop Inputs

 

A          B          C

 

JA

 

       KA

 

JB                KB

 

JC                  KC

0

0           0          0

1             X

0                 X

0                    X

1

1           0          0

X             1

1                 X

0                    X

2

0           1          0

1             X

X                 0

0                    X

3

1           1          0

X             1

X                 1

1                    X

4

0           0          1

1             X

0                 X

X                    0

5

1           0          1

X              1

0                 X

X                    1

6(0)

0           0         0

 

 

 

Table no.1: Counters Design Table for Mod-6 Counter

 Flip-Flop A:

The primary state is 0. This change to 1 after the clock pulses. Thus, JA must be 1 and KA may be 0 or 1 (that is X). In the subsequent state 1 change to 0 after the clock pulse.  Hence, JA may be 0 or 1 (that is, X) and KA must be 1.

Flip-Flop B:

The primary state is 0 and this remains unchanged after the clock pulse. Hence, JB   must be 0 and KB may be 0 or 1 (i.e. X). In the subsequent state 0 changes to 1 after the clock pulse. Hence, JB must be 1 and KB may be 0 or 1 (that is, X).

Flip-Flop C:

The primary state is 0 and this remains unchanged after the clock pulse. Hence JC must be 0 and KC may be 0 or 1 (that is, X). In the subsequent state, this remains unchanged after the clock pulse. Thus, JC must be 0 and KC may be 0 or 1 (that is, X).The JK inputs needed for such have been found with the help of the excitation table, (as in table no.1). The flip-flop input values are entered into Karnaugh maps demonstrated in Fig. a [(i), (ii), (iii), (iv), (v) and (vi)] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. As all the counter states have not been utilized, Xs (don't) are entered to denote un-utilized states. The expressions that simplified for each input have been demonstrated under each map. At last, these minimal expressions for the flip-flop inputs are utilized to draw a logic diagram for the counter demonstrated in fig.(b).

As before, the JK inputs needed for this have been found with the help of the excitation table, (as in table no.1). Such input values are entered in Karnaugh maps Fig. (a)[i to vi] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. Xs have been entered in that counter states that have not been utilized. The simplified expressions for all inputs have been demonstrated under each map and at last a logic diagram based upon these expressions is drawn and is demonstrated in fig.(b).

983_Karnaugh Maps for JA,KA,JB,KB,JC,KC.png

1325_Karnaugh Maps for JA,KA,JB,KB,JC,KC1.png

Fig.(b) Karnaugh Maps for JA,KA,JB,KB,JC,KC

1472_Logic Diagram for MOD-6 Synchronous Counter.png

Fig.(c) Logic Diagram for MOD-6 Synchronous Counter


Related Discussions:- Design a mod-6 synchronous counter

Determine the values of the output of the logic gates, Write the values of ...

Write the values of the C output for the following gates: For a(n) ________ gate, the output is zero if any of the inputs are equal to  one. For a(n) ________ gate ,the

Paging, specification of paging ram size is 12 frames

specification of paging ram size is 12 frames

Write a pseudo code to find sum of two functions, Q. Write a pseudo code to...

Q. Write a pseudo code to find sum of two functions? Let's write a pseudo code to find sum of two functions f(A) + f(B). In first algorithm we will not use locking. Process

Computer graphics, raster scan and random display technology

raster scan and random display technology

Difference between relocatable and self relocatable programs, Difference be...

Difference between relocatable and self relocatable programs. A relocatable program is one which can be processed to relocate it to a selected area of memory. For illustratio

Explain indirect cycle in control unit, Q. Explain Indirect Cycle in contro...

Q. Explain Indirect Cycle in control unit? Once an instruction is fetched the subsequent step is to fetch the operands. The instruction may have indirect and direct addressing

Artificial intelligence, 2. The Turing test has often been incorrectly inte...

2. The Turing test has often been incorrectly interpreted as being a test of whether or not a person could distinguish between responses from a computer and responses from a person

Java''s layout managers give over traditional windowing syste, Java uses la...

Java uses layout managers to lay out components in a consistent manner across all windowing platforms. As Java's layout managers aren't tied to absolute sizing and positioning, the

What is divide overflow, What is divide overflow?  The division operati...

What is divide overflow?  The division operation might result in a quotient with an overflow. Overflow happens when the length of the registers is finite and will not hold a nu

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd