Design a mod-6 synchronous counter, Computer Engineering

Assignment Help:

Design a MOD-6 synchronous counter using J-K Flip-Flops.

Ans:

Design of Mod-6 Counter:  To design the Mod-6 synchronous counter, contain six counter states (that is, from 0 to 6). For this counter, the counter design table lists the three flip-flop and their states as 0 to 6 and the 6 inputs for the 3 flip-flops. The flip-flop inputs essential to step up the counter from the now to the next state is worked out along with the help of the excitation table.  The needed counter states and the J K inputs essential for counter flip- flops are specified in the counter design table demonstrated in Table no.1.

Input pulse

 

count

Counter States

 

Flip-Flop Inputs

 

A          B          C

 

JA

 

       KA

 

JB                KB

 

JC                  KC

0

0           0          0

1             X

0                 X

0                    X

1

1           0          0

X             1

1                 X

0                    X

2

0           1          0

1             X

X                 0

0                    X

3

1           1          0

X             1

X                 1

1                    X

4

0           0          1

1             X

0                 X

X                    0

5

1           0          1

X              1

0                 X

X                    1

6(0)

0           0         0

 

 

 

Table no.1: Counters Design Table for Mod-6 Counter

 Flip-Flop A:

The primary state is 0. This change to 1 after the clock pulses. Thus, JA must be 1 and KA may be 0 or 1 (that is X). In the subsequent state 1 change to 0 after the clock pulse.  Hence, JA may be 0 or 1 (that is, X) and KA must be 1.

Flip-Flop B:

The primary state is 0 and this remains unchanged after the clock pulse. Hence, JB   must be 0 and KB may be 0 or 1 (i.e. X). In the subsequent state 0 changes to 1 after the clock pulse. Hence, JB must be 1 and KB may be 0 or 1 (that is, X).

Flip-Flop C:

The primary state is 0 and this remains unchanged after the clock pulse. Hence JC must be 0 and KC may be 0 or 1 (that is, X). In the subsequent state, this remains unchanged after the clock pulse. Thus, JC must be 0 and KC may be 0 or 1 (that is, X).The JK inputs needed for such have been found with the help of the excitation table, (as in table no.1). The flip-flop input values are entered into Karnaugh maps demonstrated in Fig. a [(i), (ii), (iii), (iv), (v) and (vi)] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. As all the counter states have not been utilized, Xs (don't) are entered to denote un-utilized states. The expressions that simplified for each input have been demonstrated under each map. At last, these minimal expressions for the flip-flop inputs are utilized to draw a logic diagram for the counter demonstrated in fig.(b).

As before, the JK inputs needed for this have been found with the help of the excitation table, (as in table no.1). Such input values are entered in Karnaugh maps Fig. (a)[i to vi] and a Boolean expression is determined for the inputs to the three flip-flops and then all expressions are simplified. Xs have been entered in that counter states that have not been utilized. The simplified expressions for all inputs have been demonstrated under each map and at last a logic diagram based upon these expressions is drawn and is demonstrated in fig.(b).

983_Karnaugh Maps for JA,KA,JB,KB,JC,KC.png

1325_Karnaugh Maps for JA,KA,JB,KB,JC,KC1.png

Fig.(b) Karnaugh Maps for JA,KA,JB,KB,JC,KC

1472_Logic Diagram for MOD-6 Synchronous Counter.png

Fig.(c) Logic Diagram for MOD-6 Synchronous Counter


Related Discussions:- Design a mod-6 synchronous counter

Differentiate aggregation and containment, Aggregation is the relationship ...

Aggregation is the relationship among the whole and a part. We can add/subtract some properties in the part (slave) side. It won't affect the entire part. Best example is Car,

What is process, In Windows, Thread is a unit of implementation. Process is...

In Windows, Thread is a unit of implementation. Process is the environment in which thread implements. Scheduler, schedules the Threads not the process. In Unix variants, Thread is

Explain bit slice ALUs, Bit Slice ALUs It was possible to manufacture ...

Bit Slice ALUs It was possible to manufacture smaller like 4 or 8 bits fixed point ALUs on a single IC chip. If these chips are constructed as expendable types then employing

What is linked list, Q. What is Linked List? A linked list is a data st...

Q. What is Linked List? A linked list is a data structure formed by zero or more nodes linked by pointers. Every node has two parts as shown in Figure below. One of them is inf

How to copy files from a drive and directory, Q. How to copy files from a d...

Q. How to copy files from a drive and directory? You can copy files from a drive and directory other that the currently selected one. However in that case, you need to speci

Describe the modes of wave propagation, Question : a) Describe the foll...

Question : a) Describe the following modes of wave propagation: - Line of sight - Ground waves - Skywaves b) Why can waves with a very low frequency be used for submar

What is reduction, What is reduction?  A reduction is a way of changing...

What is reduction?  A reduction is a way of changing one problem into another in such a way that a solution to the second problem can be used to explain the first problem.

Write the command to show the ip host table, show hosts is the command whi...

show hosts is the command which display the IP host table

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd