Design a doubly linked list, Data Structure & Algorithms

Assignment Help:

Instructions :

  • You have to design a doubly linked list container.
  • The necessary classes and their declarations are given below
  • The main() function for testing the your design is also given below. The outputs form each of the output statements are provided in the text box for your comparison.
  • So complete the program by supplying your implementations of the member functions. Some are already implemented, use as it is.

// List . h

template

class List;

template

std::ostream& operator<< (std::ostream& os, const List& l);

template

class Link;

template

class ListIterator;

template

class List{

            friend std::ostream& operator<< (std::ostream& os, const List& l);

public:

typedef ListIterator Iterator;

List() : first_(0), last_(0) {};

List(const List & other);                    // copy constructor

~List();                                                  // destructor

List & operator = (const List & rhs);  // assignment operator

T& front() const;                                                // returns the front element

void push_front(const T& e);                  // adds from front

void pop_front();                                               // deletes from front

T& back() const;                                                // returns the last element

void push_back(const T& e);                 // adds from back

void pop_back();                                               // deletes the last element

void clear();                                                       // emptied by deleting all elements in it

bool empty() const;                                           // return true if list id empty

int size() const;                                      // returns the no. of elements

Iterator begin();

Iterator end();

Iterator insert(Iterator& itr, const T& val);

void insert(Iterator& itr, int n, const T& val);

void erase(Iterator& itr);

void erase(Iterator& start, Iterator& stop);

private:

void copy(const List & other);                      // private utility only, users use =

Node* first;                                     // points to first node

Node* last;                                      // points to last node

};

template

std::ostream& operator<< (std::ostream& os, const List& lst){

            os<<"f[ ";

            Link *pp = lst.first_; //cursor to lst

            while(pp != 0){

                        if(pp != lst.first_)os<<", ";

                                    os<< pp->elem_;

                        pp = pp->next_;

            }

            os<<" ]b"<

            return os;

}

 

template                                 //  implements the node of a doubly linked list

class Node{

                        friend class List;

                        friend class ListIterator;

                        friend std::ostream& operator<< (std::ostream& os, const List& l);

            private:

                        Node(const T& e) : elem_(e), next_(0), prev_(0){} // constrructor

                        T elem_;                        // element value

                        Node* next; //  pointer to next element in the list

                        Node* prev; //  pointer to the previous element in the list

};

template                                 // implements a iterator for the list class

class ListIterator{

                        friend class List;

                        typedef ListIterator Iterator;

            public:

                        ListIterator(List* list = 0, Link* ccNode = 0) : list_(list), cNode(ccNode) {}

                        T& operator *(){

                                    //  returns the element value of the node pointed by the iterator

                        }

                        bool operator == (Iterator rhs){

                                    // returns true  if this integrator and itertrator rhs are pointing to same node                                  }

                        bool operator != (Iterator rhs){

                                    // returns false if this integrator and itertrator rhs are pointing to same node        

                        }

                        Iterator& operator ++ (int){

                                    // advance the iterator to the right

                        }

                        Iterator operator ++ (){

                                    // postfix version

                        }

                        Iterator& operator -- (int){

                                    // backward the iterator by one position to the left

                        }

                        Iterator operator -- (){

                                    // postfix  version

                        };

            private:

                        List* list;                  // pointer to current doubly linked list object

                        Node* cNode;         // pointer to the node in the doubly linked list

};

// Main driver program

#include "List.h"

#include

#include

using namespace std;

 

typedef List ListD;

typedef List ListI;

typedef List ListS;

int main(){

            ListD    x;

            x.push_front(4.4); x.push_front(3.3); x.push_front(2.2); x.push_front(1.1);

 

            ListD y(x);

            ListD z = x;

            // output is shown in the text box 1

            cout<< "x.front = "<< x.front()<< endl;   

            cout<< "List x ="<

            cout<< "x.size() ="<< x.size()<< endl;

            while(!x.empty()){

                        cout<< x.front()<< endl;

                        x.pop_front();

            }

           cout<< "x.size() now = "<< x.size()<< endl;

            cout<< "List y ="<

            cout<< y<< endl;

            cout<< "List z ="<

            cout<< z<< endl;

            ListD v;

            v = y;

            v.pop_front();

                        // output is show in the text box  2

             cout<< "List v (v = y; v.pop_front();) ="<

            cout<< v<< endl;

            ListI li;

            li.push_front(3); li.push_front(2); li.push_front(1);

                        // output is show in the text box 3

            cout<< "List li via operator <<"<

            cout<< li<< endl;

            li.push_back(22);

            li.push_back(33);

                        // output is show in the text box 4

            cout<< "li.push_back(22), li.push_back(33)"<< endl;

            cout<< li<< endl;

            cout<< "back(), pop.back()"<< endl;

            while(!li.empty()){

                        cout<< li.back()<< endl;

                        li.pop_back();

            }

           ListS ls;

            ls.push_front("abcd");

            ls.push_front("cdefgh");

            ls.push_back("back");

            cout<< ls<< endl;          // output is show in the text box 5

            ListI c5;

            for(uint i = 0; i< 5; ++i){

                        c5.push_back(i);

                        cout<< "c5.push_back(i = "<< i<< "): "<< c5;  // output is show in the text box6

            }

           cout<< "using Iterator"<< endl;   // output is show in the text box 7                   

            ListI::Iterator itr = c5.begin();

            ListI::Iterator itrb = c5.begin();

            ListI::Iterator itre = c5.end();

            if(itr == itrb)       cout<< "itr == itrb"<< endl;

            else cout<< "itr != itrb"<< endl;

            if(itr != itrb)        cout<< "itr != itrb"<< endl;

            else cout<< "itr == itrb"<< endl;

            ListI::Iterator it;

            for(it = c5.begin(); it != c5.end(); ++it){

                        cout<< *it<< ' ';             // output is show in the text box 7

            }

            // output is show in the text box 8

            cout<< "ListI::Iterator itr2 = c5.begin(), ++, ++ "<< endl;

            cout<< "c5.insert(itr2, 5, 33) "<< endl;

            ListI::Iterator itr2 = c5.begin();

            itr2++; itr2++;

            c5.insert(itr2, 5, 33);

            cout<< c5;

            return 0;

}


Related Discussions:- Design a doubly linked list

Merging 4 sorted files containing 50, Merging 4 sorted files having 50, 10,...

Merging 4 sorted files having 50, 10, 25 and 15 records will take time  O (100)

B-TREE and AVL tree diffrance, Explain process of B-TREE and what differen...

Explain process of B-TREE and what difference between AVL Tree Using Algorithms

Binary search, An unsorted array is searched through linear search that sca...

An unsorted array is searched through linear search that scans the array elements one by one until the wanted element is found. The cause for sorting an array is that we search

Pseudo code, since the gregorian calendar was introduced in 1752,a leap yea...

since the gregorian calendar was introduced in 1752,a leap year occurs every 4 years.you are to write a pseudo code to find out whether a year is a leap year.your progrm should dis

Non-recursive implementation of binary tree traversals, As we have seen, as...

As we have seen, as the traversal mechanisms were intrinsically recursive, the implementation was also easy through a recursive procedure. Though, in the case of a non-recursive me

Tree traversals, There are three kinds of tree traversals, namely, Postorde...

There are three kinds of tree traversals, namely, Postorder , Preorder and Inorder. Preorder traversal: Each of nodes is visited before its children are visited; first the roo

Methods, what is folding method?

what is folding method?

Surrounding of sub division method, Surrounding of sub division method ...

Surrounding of sub division method A polygon surrounds a viewport if it completely encloses or covers the viewport. This happens if none of its sides cuts any edge of the viewp

Depth-first search (dfs) , In this respect depth-first search (DFS) is the...

In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore

Infix expression into the postfix expression, Q. Convert the given infix ex...

Q. Convert the given infix expression into the postfix expression (also Show the steps) A ∗ (B + D)/ E - F(G + H / k ) Ans. Steps showing Infix to Post fix

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd