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Q. Describe about Coordination compounds?
The complexes show a wide variety of physical and chemical properties which are quite different from normal salts. These differences arise due to the differences in their structures. In view of a special mode of bonding called coordination' being involved in their formation. They are also termed as coordination compounds. In this unit we shall briefly look at some of the basic definitions related to coordination compounds, familiarise you with different types of isomerism possible in them as well as the basic rules for naming these compounds. We shall then explain the formation of complexes in terms of different prevalent theories. However we shall not deal with some other aspects such as their thermody namic and kinetic stability and reaction mechanism. These cannot be dealt with satisfactory in such course. Finally we shall consider a few applications of complexes in different fields.
Q. How many centigrams are in 5 kilograms? Two conversion factors are essential to solve this problem. Keep in mind that there are 1000 grams in a kilogram and 100 centigrams i
The hydration of propene The hydration of propene includes the usual mechanistic steps of alkene protonation to form a carbocation followed by the nucleophilic reaction of wate
2NO(g)+2H2O yeilds N2+2H2O Write the rate law for the pervious reaction if doubling the concentration of H2 doubles the reaction rate, and if doubling the concentration of NO incre
Chemical Properties Proteins - Hydrolysis Hydrolysis : The very simple proteins are hydrolysed by acids, alkalies or enzymes to generate amino acids. Subsequent steps are inclu
complete assignment for half life determination
I well know about electromagnetic spectrum but I did not know the any scope of spectroscopy & I want to know about I r spectra in detail & absorption spectroscopy.
Advantages of ICP-AES method: The wide applicability of ICP-AES in the quantitative analysis of various materials can be attributed to the following advantages. Rapid a
Two solutions are prepared using the same solute: Solution A: 0.27g of the solute dissolves in 27.4g of t-butanol. Solution B: 0.23g of the solute dissolves in 24.8g cyclohexane. W
The number of orbitals present in the shell with n= 4 is: (1) 16 (2) 8 (3) 18 (4) 32 Ans: 16
For sodium atom the number of electrons with m=0 will be: (1) 2 (2) 27 (3) 9 (4) 8 Ans: 7
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