Definition of a function, Mathematics

Assignment Help:

A function is a relation for which each of the value from the set the first components of the ordered pairs is related with exactly one value from the set of second components of the ordered pair.

Let's see if we can make out just what it means.  Let's take a look at the given example that will expectantly help us figure all this out.

Example:  The following relation is a function.

{(-1, 0)  (0, -3) ( 2, -3)  (3, 0)  ( 4, 5)}

Solution

From these ordered pairs we contain the following sets of first components (that means. the first number through each ordered pair) and second components (that means the second number through each ordered pair).

1st components : {-1, 0, 2, 3, 4}                      2nd   components : {0, -3, 0, 5}

 For the set of second components observed that the "-3" occurred in two ordered pairs however we only listed it once.

In order to see why this relation is a function just picks any value from the set of first components. After that, go back up to the relation and determine every ordered pair wherein this number is the first component & list all the second components from those ordered pairs. The list of second components will contain exactly one value.

For instance let's select 2 from the set of first components.  From the relation we see that there is accurately one ordered pair along with 2 as a first component, ( 2, -3) .  Thus the list of second components (that means the list of values from the set of second components) related with 2 is exactly one number, -3.

Notice that we don't care that -3 is the second component of second ordered par in the relation. That is completely acceptable.  We just don't desire there to be any more than one ordered pair along with 2 as a first component.

We looked at single value through the set of first components for our fast example here but the result will be the similar for all the other choices.  Regardless of the option of first components there will be accurately one second component related with it.

Thus this relation is a function.

In order to actually get a feel for what the definition of a function is telling us we have to probably also check out an instance of a relation that is not a function.


Related Discussions:- Definition of a function

Introduction to ones tens and more, INTRODUCTION :  We are often confronte...

INTRODUCTION :  We are often confronted with children not being able to deal with H T 0, i.e. 'hundreds', 'tens' and 'ones' (or 'units'), with comfort, though they are supposed to

Calculate moving average, Calculate Moving Average The table given bel...

Calculate Moving Average The table given below represents company sales; calculate 3 and 6 monthly moving averages, for data Months Sales

Practical geometry, Ask question draw a line parallel to given line xy at a...

Ask question draw a line parallel to given line xy at a distance of 5cm from it #Minimum 100 words accepted#

Share and dividend, i want to get market value of 10 popular shares of all ...

i want to get market value of 10 popular shares of all working days in a week

Weight, if an object weighed 11 pounds how many ounces would it weigh

if an object weighed 11 pounds how many ounces would it weigh

Determine the area of the matting, A circular print is being matted in a sq...

A circular print is being matted in a square frame. If the frame is 18 in by 18 in, and the radius of the print is 7 in, what is the area of the matting? (π = 3.14) a. 477.86 in

Inverse laplace transforms, Determining the Laplace transform of a function...

Determining the Laplace transform of a function is not terribly hard if we've found a table of transforms opposite us to use as we saw in the previous section. What we would want t

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd