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from 0->1:Int sqrt(1-x^2) Solution)
I=∫sqrt(1-x2)dx = sqrt(1-x2)∫dx - ∫{(-2x)/2sqrt(1-x2)}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x2) - ∫-x2/√(1-x2)
Let I1= ∫x2/√(1-x2) = ∫1-x2-1/√(1-x2) = ∫√(1-x2) - ∫1/√(1-x2) = ∫√(1-x2) - sin-1x = I - sin-1x
I = x√(1-x2) - I + sin-1x
2I = x√(1-x2) + sin-1x
I = x/2*√(1-x2) + 1/2*sin-1x
Within limits 0 -> 1
I = [1/2*√(1-1) + 1/2sin-11 - 1/2*√(1-0) - 1/2sin^-1(0) ] = 0 + pi/2 - 1/2 - 0 = pi/2 - 1/2
Geometric Applications to the Cross Product There are a so many geometric applications to the cross product also. Assume we have three vectors a → , b → and c → and we make
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Evaluate the following integral. ∫ (x+2 / 3√(x-3)) (dx) Solution Occasionally while faced with an integral that consists of a root we can make use of the following subs
Given, y = f(x) = 2 x 3 - 3x 2 + 4x +5 a) Use the Power function to find derivative of the function. b) Find the value of the derivative at x = 4.
how to use a micrometer
As1212uestion #Minimum 100 words accepted#
Statistical estimation This is the procedure of using statistic to estimate a population parameter This is divided into point estimation whereas an estimate of a population
HE IGHTS AND DISTANCES If the angle of elevation of cloud from a point 'h' meters above a lake is α and the angle of depression of its reflection in the lake is β , prove
im having trouble with this problem: 6tons 1500lb/5
27-125 a power -135a +225a power2
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