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from 0->1:Int sqrt(1-x^2) Solution)
I=∫sqrt(1-x2)dx = sqrt(1-x2)∫dx - ∫{(-2x)/2sqrt(1-x2)}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x2) - ∫-x2/√(1-x2)
Let I1= ∫x2/√(1-x2) = ∫1-x2-1/√(1-x2) = ∫√(1-x2) - ∫1/√(1-x2) = ∫√(1-x2) - sin-1x = I - sin-1x
I = x√(1-x2) - I + sin-1x
2I = x√(1-x2) + sin-1x
I = x/2*√(1-x2) + 1/2*sin-1x
Within limits 0 -> 1
I = [1/2*√(1-1) + 1/2sin-11 - 1/2*√(1-0) - 1/2sin^-1(0) ] = 0 + pi/2 - 1/2 - 0 = pi/2 - 1/2
Estimate the area between f ( x ) =x 3 - 5x 2 + 6 x + 5 and the x-axis by using n = 5 subintervals & all three cases above for the heights of each of the rectangle. Solution
Negative function : Several functions are not positive however. Consider the case of f (x ) =x 2 - 4 on [0,2]. If we utilizes n = 8 and the midpoints for the rectangle height w
For each of these arguments determine whether the argument is correct or incorrect and explain why. a) Everyone enrolled in the university has lived in a dormitory. Mia has never l
Systems of Equations Revisited We require doing a quick revisit of systems of equations. Let's establish with a general system of equations. a 11 x 1 + a 12 x 2 +......
Constrcut the adjacency matrix and the adjacency lists for the graph G belowr.
y+7 3y-2 --- = 1 + ---- 3 5
change 5.075 to a fraction
arrange these numbers in ascending order. -5 -7 1 2 15 0 - 25
Consider the function f(x) = 2x 2 + 1. Find the equation of the tangent to the graph of f(x) at x = 2. [NOTE: when calculating f'(2), use first principles.
Hi I have a maths question related to construction as its a construction management course...i could send some example sheets too...could it be done?
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