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from 0->1:Int sqrt(1-x^2) Solution)
I=∫sqrt(1-x2)dx = sqrt(1-x2)∫dx - ∫{(-2x)/2sqrt(1-x2)}∫dx ---->(INTEGRATION BY PARTS) = x√(1-x2) - ∫-x2/√(1-x2)
Let I1= ∫x2/√(1-x2) = ∫1-x2-1/√(1-x2) = ∫√(1-x2) - ∫1/√(1-x2) = ∫√(1-x2) - sin-1x = I - sin-1x
I = x√(1-x2) - I + sin-1x
2I = x√(1-x2) + sin-1x
I = x/2*√(1-x2) + 1/2*sin-1x
Within limits 0 -> 1
I = [1/2*√(1-1) + 1/2sin-11 - 1/2*√(1-0) - 1/2sin^-1(0) ] = 0 + pi/2 - 1/2 - 0 = pi/2 - 1/2
Need help, please anybody solve this: Consider the universal set T and its subsets A, B and C underneath as: T = {a, b, c, d e, f} A = {a, d} B = {b, c, f} C = {a, c
Describe differance between Mean vs. Mode ? Every set of numbers or data has a mean and a mode value. The mean is the average value of all the numbers in the set. The mode is t
The midpoint of the line joining (2a, 4) and (-2, 3b) is (1, 2a +1).Find the values of a & b. (Ans: a = 2, b = 2) Ans : A(2a, 4) P(1, 2a + 1) B(-2,
equivalent decimal for 25%
4.2^2x+1-9.2^x+1=0
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