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Define the Data Type Modifiers in C language?
There are three data types(int, float & double) above have the following modifiers.
1. short 2. long 3. signed 4. unsigned
The modifiers define the amount of storage allocated to the variable. The Integer quantities can be defined as short int, unsigned int or long int. Short int may need less memory than an ordinary int in word length. likewise a long int may require the same amount or more amount of memory but it will never be less than an ordinary int. An unsigned has the similar memory requirements, as an ordinary int. An unsigned int can be roughly twice as large as an ordinary int. Unsigned integer size varies from 0 to 65535 and the unsigned prefix indicates that the object is a nonnegative integer. Every unsigned type provides the same size storage as its signed equivalent. For instance int reserves the same storage as unsigned int and for the reason that a signed type reserves a sign bit an unsigned type can hold a larger positive integer than the equivalent signed type.
The following instance defines the short int variable flag:
short int flag;
The following illustration defines the unsigned long int variable ss_number as having the initial value 438888834: unsigned long ss_number = 438888834; The Data type modifiers, unsigned or signed may be explicitly applied to char while unsigned chars have values between 0 and 255 signed chars have values from -128 to 127. The modifiers long float and long double can as well be used explicitly.
Is there any difficulty with the following : char*a=NULL; char& p = *a;? A: The result is indeterminate. You must never do this. A reference has to always refer to some object.
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