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In scalar processors just one instruction is implemented per cycle which means just one instruction is issued for each cycle and only that one instruction is completed however the speed of the processor can be improved in scalar pipeline processor if multiple instructions instead of one are issued for each cycle. This concept of increasing the processor's speed by having numerous instructions for each cycle is termed a Superscalar processing. In this processing numerous instructions are issued for each cycle and numerous results are produced for each cycle. So the fundamental concept of superscalar processor is to have more instruction level parallelism.
Explain the term - ancestors The ancestors of modern age computer were mechanical and electro-mechanical instruments. This ancestry can be traced as back and seventeenth centur
Op code mnemonics: Instructions (statements) in assembly language are usually very simple, unlike those that in high-level languages. Usually, an opcode is a symbol
Q. Show the properties of Text Box? The tag is used to specify where user input is expected. It has several attributes, of which TYPE attribute is used to specify th
Multiple Instruction and Multiple Data stream (MIMD) In this association, multiple control units and multiple processing elements are prepared as in MISD. But the discrepancy i
What are SPA/GPA parameters (SAP memory) SPA/GPA parameters are field values saved globally in memory. There are two ways to use SPA/GPA parmeters: By setting field attrib
Binary codes exist for any fundamental representation. Binary codes can be created for any set of discrete elements for example colors, spectrum, musical notes, chessboard position
What is a Manifest? An assembly manifest contains all the metadata required to specify the assembly's version requirements and security identity, and all metadata required to
example of data dictionary
Simplify the Boolean expression F = C(B + C)(A + B + C). Ans. Simplification of the given Boolean Expression F = C (B +C) (A+B+C) given as F = C (B+C) (A+B+C) = CB + CC [(A+B+C
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