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Q. Define Point-to-point Communication?
The simplest form of message is a point to point communication. A message is sent from the transmitting processor to a receiving processor. Message passing in point-to-point communication can be in any 2 modes: asynchronous and synchronous. In synchronous transfer mode the next message is sent just after the acknowledgement of delivery of the last message. In this mode sequence of messages is managed. In asynchronous transfer mode no acknowledgement for delivery is needed.
Determine the registers are available in machines Typical registers, some of which are commonly available in machines. These registers are as follows:- Memory Addres
Discuss in detail Table management Techniques? An Assembler uses the subsequent tables: OPTAB: Operation Code Table consists of mnemonic operation code and machine langua
define conceptual schema
How WAP Gateway works? An significant feature of WAP is the maintain of telephony service integrated with micro browsing of data. aveAccess WAP Gateway functionss as a
We perform load testing once we are completed with interface (GUI) testing. Modern system architectures are large and difficult. Whereas one user testing primarily on functionality
Q. What is Command Prompt Interface? Operating System gives a text based interface called command prompt. With the help of command prompt commands can be issued to perform fil
The lrd_stmt function associates a character string (generally a SQL statement) with a cursor. This function sets a SQL statement to be processed.
Q. Salient features of direct addressing mode? A number of salient points about this technique are: This scheme offers a limited address space since if address field has
DOS is not a RTOS (real time Operating system), though MS DOS can be used with certain APIs to attain the RTOS functionality. For example, the RT Kernel (Real Time Kernel) which ca
Prove the equations using the Boolean algebraic theorems that is given below A‾BC + AB‾C + ABC‾+ ABC = AB + BC + AC Ans. The equation given is A‾BC + AB‾C + ABC‾+ ABC = AB + BC +
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