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Q. Define Memory For a digital computer?
For a digital computer which stores both programs and data, memory can be divided into three types: random-access memory, mass storage, and archival storage. Random-access memory includes read-and-write memory (RAM), read-only memory (ROM), programmable read-only memory (PROM), and erasable programmable read-only memory (EPROM), in which any memory location can be accessed in about the same time. The time required to access data in a mass-storage device is relative to its location in the device. Mass storage, such as magnetic disk memory, has a relatively large storage capacity and is lower in cost per bit than random access memory. Archival storage, such as magnetic tape, is long-term storage with a very large capacity, but with a very slow access time, and may need user intervention for access by the system.
Q. What do you mean by addressing and numbering? Numbering and Addressing: In data and telephone networks, end equipment are more often single units than multiple devices uni
What are the broad principals that will be applied in product design to facilitate automated assembly ?
Explain LDA, STA and DAA instructions LDA copies the data byte into accumulator from the memory location particular by the 16-bit address. STA copies the data byte from the acc
Q. Explain about Subscriber Loop System? Subscriber Loop System:Each subscriber in a telephone network is connected normally to the nearest switching office by a dedicated pair
what is an useful life time in bathtub curve?
Q. Explain about Subscriber loops signalling? In a telephone network, subscriber loop signal linger lies upon the kind of a telephone instrument used. The intra exchange signal
Avalanche Breakdown: This type of breakdown takes place when both sides of junction are lightly doped and consequently the depletion layer is large. In this case, the electric
Q. For the NOR and inverter realizations shown in Figure, find the truth table, the type of gate realized, and the expression for the logic output, in each case.
1. Given S(D1) = !Q1 X + !Q1 Q0 + Q1 !Q0 !X and S(D0) = !Q1 !Q0 !X + Q0 X + Q1 !Q0 !X A. DRAW A MINIMI
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