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Define How Passing Arrays to a Function?
A complete array can be passed to a function as an argument. The manner in which the array is passed be different from that of an ordinary variable. To get ahead of an array to a function, the array names have to appear by itself, without subscripts or brackets as an actual argument within the function call. The corresponding formal argument is written in the similar manner however it must be declared as an array within the formal argument declarations.
When declaring a one-dimensional array like a formal argument, the array name is written with a couple of empty square brackets. The size of the array isn't specific within the formal argument declaration. A few cares is required when writing function prototypes that include array arguments. An empty brace of square brackets ought to follow the name of each array argument, therefore indicating that the argument is an array. If argument names aren't included in a function declaration, after that an empty pair of square brackets must follow the array argument data type. Arguments are passed to a function by value while the arguments are ordinary variables. When an array is passed to a function though the values of the array elements aren't passed to the function. Somewhat the array name is interpreted as the address of the first array element (that is the address of the memory location containing the first array element). This address is assigned to the corresponding formal argument while the function is called.
The formal argument thus becomes a pointer to the first array element. Arguments that are passed herein manner are said to be passed by reference somewhat than by value. When a reference is made to an array element inside the function the value of the element's subscript is added to the value of the pointer to indicate the address of the specified array element. Consequently any array element can be accessed from within the function. Likewise if an array element is altered within the function the alteration will be recognized in the calling portion of the program (usually throughout the entire scope of the array).
b) Why copy constructor accepts reference to an object and not the object itself? What happens if we do otherwise?
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