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Binary search technique:-
This technique is applied to an ordered list where elements are arranged either in ascending order or descending order. The array is separated into two parts and the item being searched for is compared with item at the centre of the array. If they are equal the search is successful. Or else the search is performed in either the first half or second half of the array. If the middle element is greater than the item
Given a list containing Province, CustomerName and SalesValue (sorted by Province and CustomerName), describe an algorithm you could use that would output each CustomerName and Sal
Tree is a widely used data structure employed for representing several problems. We studied tree like a special case of acyclic graph. Though, rooted trees are most prominent of al
Adjacency list representation An Adjacency list representation of Graph G = {V, E} contains an array of adjacency lists mentioned by adj of V list. For each of the vertex u?V,
How can the third dimension be displayed on the screen The main problem in visualization is the display of three-dimensional objects and scenes on two-dimensional screens. How
Methods of Collision Resolution 1) Collision Resolution by separate chaining 2) Collision Resolution by open addressing
Decision Tree - ID3 algorithm: Imagine you only ever do one of the following four things for any weekend: go shopping watch a movie play tennis just
Define Hashing. Store the following values in a hash table of table size 11 using division method: 25, 42, 96, 101, 102, 162, and 197. In case of collision, use other hash functio
Q. Show the various passes of bubble sort on the unsorted given list 11, 15, 2, 13, 6 Ans: The given data is as follows:- Pass 1:- 11 15 2 13
B i n a ry Search Algorithm is given as follows 1. if (low > high) 2. return (-1) 3. mid = (low +high)/2; 4. if ( X = = a [mid]) 5. return (mid); 6.
1. Start 2. Get h 3. If h T=288.15+(h*-0.0065) 4. else if h T=216.65 5. else if h T=216.65+(h*0.001) 6. else if h T=228.65+(h*0.0028) 7. else if h T=270.65 8.
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